python实现简单神经网络算法

发布时间:2020-09-19 12:30:05 作者:由硬到软
来源:脚本之家 阅读:146

python实现简单神经网络算法,供大家参考,具体内容如下

python实现二层神经网络

包括输入层和输出层

import numpy as np 
 
#sigmoid function 
def nonlin(x, deriv = False): 
  if(deriv == True): 
    return x*(1-x) 
  return 1/(1+np.exp(-x)) 
 
#input dataset 
x = np.array([[0,0,1], 
       [0,1,1], 
       [1,0,1], 
       [1,1,1]]) 
 
#output dataset 
y = np.array([[0,0,1,1]]).T 
 
np.random.seed(1) 
 
#init weight value 
syn0 = 2*np.random.random((3,1))-1 
 
for iter in xrange(100000): 
  l0 = x             #the first layer,and the input layer  
  l1 = nonlin(np.dot(l0,syn0))  #the second layer,and the output layer 
 
 
  l1_error = y-l1 
 
  l1_delta = l1_error*nonlin(l1,True) 
 
  syn0 += np.dot(l0.T, l1_delta) 
print "outout after Training:" 
print l1 
import numpy as np 
 
#sigmoid function 
def nonlin(x, deriv = False): 
  if(deriv == True): 
    return x*(1-x) 
  return 1/(1+np.exp(-x)) 
 
#input dataset 
x = np.array([[0,0,1], 
       [0,1,1], 
       [1,0,1], 
       [1,1,1]]) 
 
#output dataset 
y = np.array([[0,0,1,1]]).T 
 
np.random.seed(1) 
 
#init weight value 
syn0 = 2*np.random.random((3,1))-1 
 
for iter in xrange(100000): 
  l0 = x             #the first layer,and the input layer  
  l1 = nonlin(np.dot(l0,syn0))  #the second layer,and the output layer 
 
 
  l1_error = y-l1 
 
  l1_delta = l1_error*nonlin(l1,True) 
 
  syn0 += np.dot(l0.T, l1_delta) 
print "outout after Training:" 
print l1 

这里,
l0:输入层

l1:输出层

syn0:初始权值

l1_error:误差

l1_delta:误差校正系数

func nonlin:sigmoid函数

python实现简单神经网络算法

可见迭代次数越多,预测结果越接近理想值,当时耗时也越长。

python实现三层神经网络

包括输入层、隐含层和输出层

import numpy as np 
 
def nonlin(x, deriv = False): 
  if(deriv == True): 
    return x*(1-x) 
  else: 
    return 1/(1+np.exp(-x)) 
 
#input dataset 
X = np.array([[0,0,1], 
       [0,1,1], 
       [1,0,1], 
       [1,1,1]]) 
 
#output dataset 
y = np.array([[0,1,1,0]]).T 
 
syn0 = 2*np.random.random((3,4)) - 1 #the first-hidden layer weight value 
syn1 = 2*np.random.random((4,1)) - 1 #the hidden-output layer weight value 
 
for j in range(60000): 
  l0 = X            #the first layer,and the input layer  
  l1 = nonlin(np.dot(l0,syn0)) #the second layer,and the hidden layer 
  l2 = nonlin(np.dot(l1,syn1)) #the third layer,and the output layer 
 
 
  l2_error = y-l2    #the hidden-output layer error 
 
  if(j%10000) == 0: 
    print "Error:"+str(np.mean(l2_error)) 
 
  l2_delta = l2_error*nonlin(l2,deriv = True) 
 
  l1_error = l2_delta.dot(syn1.T)   #the first-hidden layer error 
 
  l1_delta = l1_error*nonlin(l1,deriv = True) 
 
  syn1 += l1.T.dot(l2_delta) 
  syn0 += l0.T.dot(l1_delta) 
print "outout after Training:" 
print l2 
import numpy as np 
 
def nonlin(x, deriv = False): 
  if(deriv == True): 
    return x*(1-x) 
  else: 
    return 1/(1+np.exp(-x)) 
 
#input dataset 
X = np.array([[0,0,1], 
       [0,1,1], 
       [1,0,1], 
       [1,1,1]]) 
 
#output dataset 
y = np.array([[0,1,1,0]]).T 
 
syn0 = 2*np.random.random((3,4)) - 1 #the first-hidden layer weight value 
syn1 = 2*np.random.random((4,1)) - 1 #the hidden-output layer weight value 
 
for j in range(60000): 
  l0 = X            #the first layer,and the input layer  
  l1 = nonlin(np.dot(l0,syn0)) #the second layer,and the hidden layer 
  l2 = nonlin(np.dot(l1,syn1)) #the third layer,and the output layer 
 
 
  l2_error = y-l2    #the hidden-output layer error 
 
  if(j%10000) == 0: 
    print "Error:"+str(np.mean(l2_error)) 
 
  l2_delta = l2_error*nonlin(l2,deriv = True) 
 
  l1_error = l2_delta.dot(syn1.T)   #the first-hidden layer error 
 
  l1_delta = l1_error*nonlin(l1,deriv = True) 
 
  syn1 += l1.T.dot(l2_delta) 
  syn0 += l0.T.dot(l1_delta) 
print "outout after Training:" 
print l2 

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持亿速云。

推荐阅读:
  1. lvs算法简单介绍
  2. 用Python实现BP神经网络(附代码)

免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。

python 神经网络 实现简单

上一篇:windows+office激活脚本更新

下一篇:浅谈Spring Data如何简化数据操作的方法

相关阅读

您好,登录后才能下订单哦!

密码登录
登录注册
其他方式登录
点击 登录注册 即表示同意《亿速云用户服务条款》