java如何通过XPath解析xml节点

发布时间:2020-07-14 10:31:03 作者:Leah
来源:亿速云 阅读:164

今天就跟大家聊聊有关java如何通过XPath解析xml节点,可能很多人都不太了解,为了让大家更加了解,小编给大家总结了以下内容,希望大家根据这篇文章可以有所收获。

import java.io.File;
import java.io.FileInputStream;
 
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
 
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
 
public class FindElementsByAbsoluteLocationWithXPath {
 
    public static void main(String[] args) throws Exception {
 
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        dbf.setValidating(false);
        DocumentBuilder db = dbf.newDocumentBuilder();
 
        Document doc = db.parse(new FileInputStream(new File("in.xml")));
 
        XPathFactory factory = XPathFactory.newInstance();
 
        XPath xpath = factory.newXPath();
 
        String expression;
        Node node;
        NodeList nodeList;
 
        // 1. root element
        expression = "/*";
        node = (Node) xpath.evaluate(expression, doc, XPathConstants.NODE);
        System.out.println("1. " + node.getNodeName());
 
        // 2. root element (by name)
        expression = "/rss";
        node = (Node) xpath.evaluate(expression, doc, XPathConstants.NODE);
        System.out.println("2. " + node.getNodeName());
 
        // 3. element under rss
        expression = "/rss/channel";
        node = (Node) xpath.evaluate(expression, doc, XPathConstants.NODE);
        System.out.println("3. " + node.getNodeName());
 
        // 4. all elements under rss/channel
        expression = "/rss/channel/*";
        nodeList = (NodeList) xpath.evaluate(expression, doc, XPathConstants.NODESET);
        System.out.print("4. ");
        for (int i = 0; i < nodeList.getLength(); i++) {
            System.out.print(nodeList.item(i).getNodeName() + " ");
        }
        System.out.println();
 
        // 5. all title elements in the document
        expression = "//title";
        nodeList = (NodeList) xpath.evaluate(expression, doc, XPathConstants.NODESET);
        System.out.print("5. ");
        for (int i = 0; i < nodeList.getLength(); i++) {
            System.out.print(nodeList.item(i).getNodeName() + " ");
        }
        System.out.println();
 
        // 6. all elements in the document except title
        expression = "//*[name() != 'title']";
        nodeList = (NodeList) xpath.evaluate(expression, doc, XPathConstants.NODESET);
        System.out.print("6. ");
        for (int i = 0; i < nodeList.getLength(); i++) {
            System.out.print(nodeList.item(i).getNodeName() + " ");
        }
        System.out.println();
 
        // 7. all elements with at least one child element
        expression = "//*[*]";
        nodeList = (NodeList) xpath.evaluate(expression, doc, XPathConstants.NODESET);
        System.out.print("7. ");
        for (int i = 0; i < nodeList.getLength(); i++) {
            System.out.print(nodeList.item(i).getNodeName() + " ");
        }
        System.out.println();
 
        // 8. all level-5 elements (the root being at level 1)
        expression = "/*/*/*/*";
        nodeList = (NodeList) xpath.evaluate(expression, doc, XPathConstants.NODESET);
        System.out.print("8. ");
        for (int i = 0; i < nodeList.getLength(); i++) {
            System.out.print(nodeList.item(i).getNodeName() + " ");
        }
        System.out.println();
 
    }
 
}

Input:

<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0">
    <channel>
        <title>Java Tutorials and Examples 2</title>
        <language>en-us</language>
        <item>
            <title><![CDATA[Java Tutorials 2]]></title>
            <link>http://www.javacodegeeks.com/</link>
        </item>
        <item>
            <title><![CDATA[Java Examples 2]]></title>
            <link>http://examples.javacodegeeks.com/</link>
        </item>
    </channel>
</rss>

输出:

1. rss
2. rss
3. channel
4. title language item item
5. title title title
6. rss channel language item link item link
7. rss channel item item
8. title link title link

看完上述内容,你们对java如何通过XPath解析xml节点有进一步的了解吗?如果还想了解更多知识或者相关内容,请关注亿速云行业资讯频道,感谢大家的支持。

推荐阅读:
  1. html使用xpath解析xml
  2. dom和xpath解析xml

免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。

java xpath xml节点

上一篇:Day01,Python数据类型及常见操作

下一篇:如何实现XML与现代CGI应用程序

相关阅读

您好,登录后才能下订单哦!

密码登录
登录注册
其他方式登录
点击 登录注册 即表示同意《亿速云用户服务条款》