150行Python代码实现带界面的数独游戏

发布时间:2020-08-28 08:10:22 作者:HoLoong
来源:脚本之家 阅读:261

今天闲着没事干,以前做过html+js版的数独,这次做个python版本的,界面由pygame完成,数独生成由递归算法实现,由shuffle保证每次游戏都是不一样的情况,have fun;

功能列表:

 游戏界面

初始界面

150行Python代码实现带界面的数独游戏

过程中界面

150行Python代码实现带界面的数独游戏

运行方式

python main.py 15

这里的15表示需要填入的空格数量为15,理论上这个值越大,难度就越高,大家可以随机调整,或者设置容易、简单、困难、地狱等对应不同的值即可,很方便修改;

程序分析

界面部分

这部分很简单的通过pygame来实现,主要使用了其中的主循环、鼠标键盘监听、画矩形线条、字体、颜色控制等,理解起来很容易,对于这部分不太熟悉的同学,这样理解就好: pygame的主循环中一方面负责接收用户输入,一般就是鼠标和键盘,另一方面负责实时更新界面显示内容 ;

对于界面上各部分内容的绘制的函数封装

# 绘制背景部分,这里就是9*9的九宫格
def draw_background():
  # white background
  screen.fill(COLORS['white'])

  # draw game board
  pygame.draw.rect(screen,COLORS['black'],(0,0,300,900),5)
  pygame.draw.rect(screen,COLORS['black'],(300,0,300,900),5)
  pygame.draw.rect(screen,COLORS['black'],(600,0,300,900),5)

  pygame.draw.rect(screen,COLORS['black'],(0,0,900,300),5)
  pygame.draw.rect(screen,COLORS['black'],(0,300,900,300),5)
  pygame.draw.rect(screen,COLORS['black'],(0,600,900,300),5)

# 将用户选中的各自背景改为蓝色块表示选中
def draw_choose():
  pygame.draw.rect(screen,COLORS['blue'],(cur_j*100+5,cur_i*100+5,100-10,100-10),0)

# 绘制九宫格中的数字,包括本来就有的,以及用户填入的,本来就在的用灰色,用户填入的如何合法则为绿色,否则为红色,是一种提示
def draw_number():
  for i in range(len(MATRIX)):
    for j in range(len(MATRIX[0])):
      _color = check_color(MATRIX,i,j) if (i,j) in BLANK_IJ else COLORS['gray']
      txt = font80.render(str(MATRIX[i][j] if MATRIX[i][j] not in [0,'0'] else ''),True,_color)
      x,y = j*100+30,i*100+10
      screen.blit(txt,(x,y))

# 绘制最下方的当前空格子数量以及用户的操作数量
def draw_context():
  txt = font100.render('Blank:'+str(cur_blank_size)+'  Change:'+str(cur_change_size),True,COLORS['black'])
  x,y = 10,900
  screen.blit(txt,(x,y))

主循环中对上述函数的调用以及鼠标键盘事件处理

# 主循环,负责监听鼠标键盘时间,以及刷新界面内容,以及检查是否赢得了游戏
running = True
while running:
  for event in pygame.event.get():
    if event.type == pygame.QUIT:
      running = False
      break
    elif event.type == pygame.MOUSEBUTTONDOWN:
      cur_j,cur_i = int(event.pos[0]/100),int(event.pos[1]/100)
    elif event.type == event.type == pygame.KEYUP:
      if chr(event.key) in ['1','2','3','4','5','6','7','8','9'] and (cur_i,cur_j) in BLANK_IJ:
        MATRIX[cur_i][cur_j] = int(chr(event.key))
        cur_blank_size = sum([1 if col==0 or col=='0' else 0 for row in MATRIX for col in row])
        cur_change_size +=1
  # background
  draw_background()
  # choose item
  draw_choose()
  # numbers
  draw_number()
  # point
  draw_context()
  # flip
  pygame.display.flip()

  # check win or not
  if check_win(MATRIX_ANSWER,MATRIX):
    print('You win, smarty ass!!!')
    break

pygame.quit()

生成表示数独的二维数组

相对于界面部分,这部分在逻辑上要难一些,思路以递归为核心,辅以随机性,得到一个每次生成都不一致的数独游戏,生成思路简单描述如下:

生成过程代码

递归的一个优势是通常代码都很短,当然阅读性不强,欢迎大佬们改为循环;

def shuffle_number(_list):
  random.shuffle(_list)
  return _list

def check(matrix,i,j,number):
  if number in matrix[i]:
    return False
  if number in [row[j] for row in matrix]:
    return False
  group_i,group_j = int(i/3),int(j/3)
  if number in [matrix[i][j] for i in range(group_i*3,(group_i+1)*3) for j in range(group_j*3,(group_j+1)*3)]:
    return False
  return True

def build_game(matrix,i,j,number):
  if i>8 or j>8:
    return matrix
  if check(matrix,i,j,number):
    _matrix = [[col for col in row] for row in matrix]
    _matrix[i][j] = number
    next_i,next_j = (i+1,0) if j==8 else (i,j+1)
    for _number in shuffle_number(number_list):
      __matrix = build_game(_matrix,next_i,next_j,_number)
      if __matrix and sum([sum(row) for row in __matrix])==(sum(range(1,10))*9):
        return __matrix
  return None

随机覆盖数独数组中的N个位置

def give_me_a_game(blank_size=9):
  matrix_all = build_game(matrix,0,0,random.choice(number_list))
  set_ij = set()
  while len(list(set_ij))<blank_size:
    set_ij.add(str(random.choice([0,1,2,3,4,5,6,7,8]))+','+str(random.choice([0,1,2,3,4,5,6,7,8])))
  matrix_blank = [[col for col in row] for row in matrix_all]
  blank_ij = []
  for ij in list(set_ij):
    i,j = int(ij.split(',')[0]),int(ij.split(',')[1])
    blank_ij.append((i,j))
    matrix_blank[i][j] = 0
  return matrix_all,matrix_blank,blank_ij

最后附上全部代码

大家也可以直接从我的 Github仓库 fork下来直接运行;

main.py:主流程+界面+执行

import sys

import pygame
from pygame.color import THECOLORS as COLORS

from build import print_matrix,give_me_a_game,check

def draw_background():
  # white background
  screen.fill(COLORS['white'])

  # draw game board
  pygame.draw.rect(screen,COLORS['black'],(0,0,300,900),5)
  pygame.draw.rect(screen,COLORS['black'],(300,0,300,900),5)
  pygame.draw.rect(screen,COLORS['black'],(600,0,300,900),5)

  pygame.draw.rect(screen,COLORS['black'],(0,0,900,300),5)
  pygame.draw.rect(screen,COLORS['black'],(0,300,900,300),5)
  pygame.draw.rect(screen,COLORS['black'],(0,600,900,300),5)

def draw_choose():
  pygame.draw.rect(screen,COLORS['blue'],(cur_j*100+5,cur_i*100+5,100-10,100-10),0)

def check_win(matrix_all,matrix):
  if matrix_all == matrix:
    return True
  return False

def check_color(matrix,i,j):
  _matrix = [[col for col in row]for row in matrix]
  _matrix[i][j] = 0
  if check(_matrix,i,j,matrix[i][j]):
    return COLORS['green']
  return COLORS['red']

def draw_number():
  for i in range(len(MATRIX)):
    for j in range(len(MATRIX[0])):
      _color = check_color(MATRIX,i,j) if (i,j) in BLANK_IJ else COLORS['gray']
      txt = font80.render(str(MATRIX[i][j] if MATRIX[i][j] not in [0,'0'] else ''),True,_color)
      x,y = j*100+30,i*100+10
      screen.blit(txt,(x,y))

def draw_context():
  txt = font100.render('Blank:'+str(cur_blank_size)+'  Change:'+str(cur_change_size),True,COLORS['black'])
  x,y = 10,900
  screen.blit(txt,(x,y))

if __name__ == "__main__":
  # init pygame
  pygame.init()
  
  # contant
  SIZE = [900,1000]
  font80 = pygame.font.SysFont('Times', 80)
  font100 = pygame.font.SysFont('Times', 90)
  
  # create screen 500*500
  screen = pygame.display.set_mode(SIZE)
  
  # variable parameter
  cur_i, cur_j = 0,0
  cur_blank_size = int(sys.argv[1])
  cur_change_size = 0
  
  # matrix abount
  MATRIX_ANSWER,MATRIX,BLANK_IJ = give_me_a_game(blank_size=cur_blank_size)
  print(BLANK_IJ)
  print_matrix(MATRIX)
  
  # main loop
  running = True
  while running:
    for event in pygame.event.get():
      if event.type == pygame.QUIT:
        running = False
        break
      elif event.type == pygame.MOUSEBUTTONDOWN:
        cur_j,cur_i = int(event.pos[0]/100),int(event.pos[1]/100)
      elif event.type == event.type == pygame.KEYUP:
        if chr(event.key) in ['1','2','3','4','5','6','7','8','9'] and (cur_i,cur_j) in BLANK_IJ:
          MATRIX[cur_i][cur_j] = int(chr(event.key))
          cur_blank_size = sum([1 if col==0 or col=='0' else 0 for row in MATRIX for col in row])
          cur_change_size +=1
    # background
    draw_background()
    # choose item
    draw_choose()
    # numbers
    draw_number()
    # point
    draw_context()
    # flip
    pygame.display.flip()
  
    # check win or not
    if check_win(MATRIX_ANSWER,MATRIX):
      print('You win, smarty ass!!!')
      break
  
  pygame.quit()

build.py:生成数独数组部分

import random

def print_matrix(matrix):
  print('—'*19)
  for row in matrix:
    print('|'+' '.join([str(col) for col in row])+'|')
  print('—'*19)

def shuffle_number(_list):
  random.shuffle(_list)
  return _list

def check(matrix,i,j,number):
  if number in matrix[i]:
    return False
  if number in [row[j] for row in matrix]:
    return False
  group_i,group_j = int(i/3),int(j/3)
  if number in [matrix[i][j] for i in range(group_i*3,(group_i+1)*3) for j in range(group_j*3,(group_j+1)*3)]:
    return False
  return True

def build_game(matrix,i,j,number):
  if i>8 or j>8:
    return matrix
  if check(matrix,i,j,number):
    _matrix = [[col for col in row] for row in matrix]
    _matrix[i][j] = number
    next_i,next_j = (i+1,0) if j==8 else (i,j+1)
    for _number in shuffle_number(number_list):
      #_matrixs.append(build_game(_matrix,next_i,next_j,_number))
      __matrix = build_game(_matrix,next_i,next_j,_number)
      if __matrix and sum([sum(row) for row in __matrix])==(sum(range(1,10))*9):
        return __matrix
  #return _matrixs
  return None

def give_me_a_game(blank_size=9):
  matrix_all = build_game(matrix,0,0,random.choice(number_list))
  set_ij = set()
  while len(list(set_ij))<blank_size:
    set_ij.add(str(random.choice([0,1,2,3,4,5,6,7,8]))+','+str(random.choice([0,1,2,3,4,5,6,7,8])))
  matrix_blank = [[col for col in row] for row in matrix_all]
  blank_ij = []
  for ij in list(set_ij):
    i,j = int(ij.split(',')[0]),int(ij.split(',')[1])
    blank_ij.append((i,j))
    matrix_blank[i][j] = 0
  return matrix_all,matrix_blank,blank_ij

number_list = [1,2,3,4,5,6,7,8,9]
matrix = [([0]*9) for i in range(9)]
if __name__ == "__main__":
  print_matrix(build_game(matrix,0,0,random.choice(number_list)))

总结

如果刻意减少代码的话,实际应该控制在100行以内,这也充分表达了python的强大,确实可以在很短的时间内完成一些看似复杂的工作,这个例子供一些同学上手python个人觉得还是不错的,没有太复杂的用法,对界面开发有一点点了解,对递归有一些理解基本就能完全掌握这份代码,希望大家玩的开心,挑战一下50个空格呗,哈哈,反正我没通过,太难了。。。。

最后

大家可以到我的Github上看看有没有其他需要的东西,目前主要是自己做的机器学习项目、Python各种脚本工具、有意思的小项目以及Follow的大佬、Fork的项目等:

https://github.com/NemoHoHaloAi

到此这篇关于150行Python代码实现带界面的数独游戏的文章就介绍到这了,更多相关Python 数独游戏内容请搜索亿速云以前的文章或继续浏览下面的相关文章希望大家以后多多支持亿速云!

作者:Ho Loong
Github:https://github.com/NemoHoHaloAi
Kaggle:https://www.kaggle.com/holoong9291

推荐阅读:
  1. python 实现数独游戏
  2. python怎么实现数独游戏

免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。

python 数独游戏 面的

上一篇:transform python环境快速配置方法

下一篇:JavaScript实现大图轮播效果

相关阅读

您好,登录后才能下订单哦!

密码登录
登录注册
其他方式登录
点击 登录注册 即表示同意《亿速云用户服务条款》