python实现按首字母分类查找功能

发布时间:2020-09-11 23:34:52 作者:强强强子
来源:脚本之家 阅读:273

本文实例为大家分享了python实现按首字母分类查找的具体代码,供大家参考,具体内容如下

要求:

1.自己查找一些英文词汇,存储到某个容器类中
2.根据英文词汇的首字母进行分类,类似于手机通讯簿中的快速查找功能
3.根据用户输入的字母,找到该字母开头的所有单词

#coding=utf-8
lexicons=["the","be","of","and","A","to","in","he","have","it","that","for","they","I","with","as","not","on","she","at","by","this","we","you","do","but","from","or","which","one","would","all","will","there","say","who","make","when","can"]
while True:
 startLetter=raw_input("输入一个字母,列出所有以此字母开头的单词:")
 if len(startLetter)!=1:
 print "必须是一个字母"
 else:
 reLexicons=[] #结果列表
 for x in xrange(len(lexicons)):
  lexicon=lexicons[x]
  if lexicon[0].lower()==startLetter.lower():#都转为小写后比较 开头字母不区分大小写
  reLexicons.append(lexicon)
 if len(reLexicons)==0:
  print "没有结果"
 else:
  for x in xrange(len(reLexicons)):
  print reLexicons[x]

上面的代码没有走第二步,如下代码 使用字典解决第二步

#coding=utf-8
'''
边遍历,边构造 key value 
'''
lexicons=["the","be","of","and","A","to","in","he","have","it","that","for","they","I","with","as","not","on","she","at","by","this","we","you","do","but","from","or","which","one","would","all","will","there","say","who","make","when","can"]
lexiconDict={}
#分类 保存字典中
lexiconLen=len(lexicons)
for x in xrange(len(lexicons)):
 lexicon=lexicons[x]
 startLetter=lexicon[0]
 dictLexicons=lexiconDict.get(startLetter,[])
  #空列表说明没有Key 则添加Key 否则追加Key对应的Value
 if len(dictLexicons)==0:
 lexiconDict[startLetter]=[lexicons[x]]
 else:
 dictLexicons.append(lexicons[x])
while True:
 startLetter=raw_input("输入一个字母,列出所有以此字母开头的单词:")
 if len(startLetter)!=1:
 print "必须是一个字母"
 else:
 lexicons=lexiconDict.get(startLetter.lower(),[])
 if len(lexicons)==0:
  print "没有结果"
 else:
  for x in lexicons:
  print x

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持亿速云。

推荐阅读:
  1. Python实现二分查找
  2. 【cocosbuilder】资源查找功能

免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。

python 字母分类 查找

上一篇:Python中函数的基本定义与调用及内置函数详解

下一篇:python批量赋值操作实例

相关阅读

您好,登录后才能下订单哦!

密码登录
登录注册
其他方式登录
点击 登录注册 即表示同意《亿速云用户服务条款》