IOS json 解析遇到错误问题解决办法

发布时间：2020-09-20 13:57:08 作者：lqh
来源：脚本之家阅读：166

概要：

Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn't be completed. (Cocoa error 3840.)" (Unescaped control character around character 1419.) UserInfo=0x1563cdd0 {NSDebugDescription=Unescaped control character around character 1419.}

之前解析json的时候都是标准格式，json数据当中没有 \n \r \t 等制表符。

今天在解析的时候发现json解析时好时坏，用在线json解析也米有问题。找了半天终于发现是制表符在作怪，由于标准的json解析是不允许有这几个制表符的。所以在收到保温的时候我们需要把这几个制表符给过滤掉。

NSString * responseString = [request responseString];

responseString = [responseString stringByReplacingOccurrencesOfString:@"\r\n" withString:@""];

responseString = [responseString stringByReplacingOccurrencesOfString:@"\n" withString:@""];

responseString = [responseString stringByReplacingOccurrencesOfString:@"\t" withString:@""];

NSLog(@"responseString = %@",responseString);

SBJsonParser *parser = [[[SBJsonParser alloc]init] autorelease];

id returnObject = [parser objectWithString:responseString];

NSDictionary *userInfo = nil;

NSArray *userArr = nil;

if ([returnObject isKindOfClass:[NSDictionary class]]) {

if (userInfo) {

[userArr release];

}

userInfo = (NSDictionary*)returnObject;

}

else if ([returnObject isKindOfClass:[NSArray class]]) {

userArr = (NSArray*)returnObject;

}

NSError* e = nil;

//系统自带的解析方式。

NSDictionary * userInfo = [NSJSONSerialization JSONObjectWithData:[jsonString dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingMutableLeaves error:&e];

if (e) {

NSLog(@"%@",e);

}

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IOS json 解析遇到错误问题解决办法

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