怎么在Struts2中利用OGNL表达式对map进行遍历

发布时间:2020-12-07 16:48:00 作者:Leah
来源:亿速云 阅读:409

这篇文章给大家介绍怎么在Struts2中利用OGNL表达式对map进行遍历,内容非常详细,感兴趣的小伙伴们可以参考借鉴,希望对大家能有所帮助。

一.Action中的代码:MapAction.java

package com.zx.demo.action;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import com.opensymphony.xwork2.ActionSupport;
import com.zx.demo.model.Product;
import com.zx.demo.model.Student;
public class MapAction extends ActionSupport
{  
 private Map<String,String> map;
 private Map<String,Student> studentMap;
 private Map<String,String[]> arrayMap;
 private Map<String,List<Student>> listMap;  
 //这里省略get set方法
 public String testMap(){  
map=new HashMap<String,String>();
 map.put("1", "one");
 map.put("2", "two");
studentMap=new HashMap<String,Student>();
studentMap.put("student1",new Student(new Long(1),"20034140201","张三1","男",25));
studentMap.put("student2",new Student(new Long(2),"20034140202","张三2","女",26));
studentMap.put("student3",new Student(new Long(3),"20034140202","张三3","男",27));
arrayMap=new HashMap<String,String[]>();
arrayMap.put("arr1", new String[]{"1","2003401","leejie","male","20"});
arrayMap.put("arr2", new String[]{"2","2003402","huanglie","male","25"});
arrayMap.put("arr3", new String[{"3","2003403","lixiaoning","male","21"});
listMap=new HashMap<String,List<Student>>();
  List<Student> list1=new ArrayList<Student>();
list1.add(new Student(new Long(1),"20034140201","张三1","男",25));
list1.add(new Student(new Long(2),"20034140202","张三2","男",25));
list1.add(new Student(new Long(3),"20034140203","张三3","男",25));
  listMap.put("class1", list1);
 List<Student> list2=new ArrayList<Student>();
list2.add(new Student(new Long(1),"20034140301","李四1","男",20));
list2.add(new Student(new Long(2),"20034140302","李四2","男",21));
list2.add(new Student(new Long(3),"20034140303","李四3","男",22));
list2.add(new Student(new Long(4),"20034140304","李四4","男",23));
  listMap.put("class2", list2);
return SUCCESS;  
  }  
}

二.前端测试页面:testMap.jsp

Java代码

<%@ page
contentType="text/html;charset=UTF-8"
%> 
<%@ taglib prefix="s"
uri="/struts-tags" %>
 <html>
<head>
<title>struts2中的map遍历总结</title>
</head>
<body>
<b>1.map中的key为String,value为String字符串</b><br>
   <s:iterator value="map" id="column">
   <s:property value="#column"/><br>
 key: <s:property value="key"/><br>
 value:<s:property value="value"/><br>
   </s:iterator> 
******************************************<br>
 <table border="1" width="50%" cellspacing="0" cellpadding="0">
<tr>
 <td>key=value</td>
 <td>ID</td>
 <td>num</td>
 <td>name</td>
 <td>sex</td>
 <td>age</td>
</tr>
******************************************<br>
 <b>2.map中的key为String,value为Student对象</b>
<s:iterator value="studentMap" id="column">
<tr>
 <td>
  <s:property value="#column"/></td>
 <td>
  <s:property value="value.id"/></td>
 <td>
  <s:property value="value.num"/></td>
 <td>
  <s:property value="value.name"/></td>
 <td>
   <s:property value="value.sex"/></td>
 <td>
   <s:property value="value.age"/></td>
 </tr>
</s:iterator>
</table>
 <p> 
 
<table border="1" width="50%" cellspacing="0" cellpadding="0">
 <tr>
   <td>key=value</td>
   <td>ID</td>
   <td>num</td>
   <td>name</td>
   <td>sex</td>
   <td>age</td>
 </tr>
******************************************<br>
<b>3.map中的key为String,value为String数组</b> 
<s:iterator value="arrayMap" id="column">
<tr>
 <td><s:property value="#column"/></td>
 <td><s:property value="value[0]"/></td>
 <td><s:property value="value[1]"/></td>
 <td><s:property value="value[2]"/></td>
 <td><s:property value="value[3]"/></td>
 <td><s:property value="value[4]"/></td>
</tr>
</s:iterator>
</table>
<p> 
<table border="1" width="50%" cellspacing="0" cellpadding="0">
<tr>
 <td>class</td>
  <td>ID</td>
  <td>num</td>
  <td>name</td>
  <td>sex</td>
  <td>age</td>
</tr>
 ******************************************<br>
<b>4.map中的key为String,value为list集合</b>  
<s:iterator value="listMap" id="column">
 <s:set name="total" value="#column.value.size"/>
 <s:iterator value="#column.value" status="s">
<tr>
 <s:if test="#s.first">
  <td rowspan="${total}">
  <s:property value="#column.key"/>
  </td>
 </s:if> 
   <td>
   <s:property value="id"/>
   </td>
   <td>
   <s:property value="num"/>
   </td>
   <td>
   <s:property value="name"/>
   </td>
   <td><s:property value="sex"/></td>
   <td><s:property value="age"/></td>
</tr>
</s:iterator>
</s:iterator>
 </table>
</body>
</html> 

附:map的类型为Map<Integer,List(Menu)>在前端遍历,session.powerList存放的类型是:List(Menu)

<s:iterator value="map" id="mapList">
   <s:if test="#mapList.key==0"><!-key为0的是父级菜单->
   <s:iterator value="#mapList.value" id="map">
    <li class="current"><!--遍历父级菜单,取得其名字-->  
   <b><s:property value="#map.menuName" /></b></a>
     <ul>
     <s:iterator value="#session.powerList" id="power">
   <!--遍历父级菜单下的所用子菜单-->
      <s:if test="#power.menuFatherId==#map.menuId">
    <li><a onClick="funFrame('admin/<s:property value="#power.menuUrl" />')" ><s:property value="#power.menuName" /></a>
    </li>
       </s:if>
     </s:iterator>
     </ul>
     </li>
     </s:iterator>
     </s:if>
     </s:iterator>

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struts2 遍历 ognl表达式

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