create or replace function comm.F_upper_money(p_num in number default null)
		
		
			  return nvarchar2 is
		
		
			  /*Ver:1.0 Created By xsb on 2003-8-18 For:
		
		
			  将金额数字(单位元)转换为大写(采用从低至高算法)
		
		
			  数字整数部分不得超过16位,可以是负数。
		
		
			  Ver:1.1 Modified By xsb on 2003-8-20 For:个位数处理也放在For循环中。
		
		
			  Ver:1.2 Modified By xsb on 2003-8-22 For:分后不带整字。
		
		
			  Ver:1.3 Modified By xsb on 2003-8-28 For:完善测试用例。
		
		
			  测试用例:
		
		
			  SET HEAD OFF
		
		
			  SET FEED OFF
		
		
			  select '无参数时='||f_upper_money() from dual;
		
		
			  select 'null='||f_upper_money(null) from dual;
		
		
			  select '0='||f_upper_money(0) from dual;
		
		
			  select '0.01='||f_upper_money(0.01) from dual;
		
		
			  select '0.126='||f_upper_money(0.126) from dual;
		
		
			  select '01.234='||f_upper_money(01.234) from dual;
		
		
			  select '10='||f_upper_money(10) from dual;
		
		
			  select '100.1='||f_upper_money(100.1) from dual;
		
		
			  select '100.01='||f_upper_money(100.01) from dual;
		
		
			  select '10000='||f_upper_money(10000) from dual;
		
		
			  select '10012.12='||f_upper_money(10012.12) from dual;
		
		
			  select '20000020.01='||f_upper_money(20000020.01) from dual;
		
		
			  select '3040506708.901='||f_upper_money(3040506708.901) from dual;
		
		
			  select '40005006078.001='||f_upper_money(40005006078.001) from dual;
		
		
			  select '-123456789.98='||f_upper_money(-123456789.98) from dual;
		
		
			  select '123456789123456789.89='||f_upper_money(123456789123456789.89) from dual;
		
		
			
		
		
			  */
		
		
			  Result      nvarchar2(100); --返回字符串
		
		
			  num_round   nvarchar2(100) := to_char(abs(round(p_num, 2))); --转换数字为小数点后2位的字符(正数)
		
		
			  num_left    nvarchar2(100); --小数点左边的数字
		
		
			  num_right   nvarchar2(2); --小数点右边的数字
		
		
			  str1        nchar(10) := '零壹贰叁肆伍陆柒捌玖'; --数字大写
		
		
			  str2        nchar(16) := '元拾佰仟万拾佰仟亿拾佰仟万拾佰仟'; --数字位数(从低至高)
		
		
			  num_pre number(1) := 1; --前一位上的数字
		
		
			  num_current number(1); --当前位上的数字
		
		
			  num_count number := 0; --当前数字位数
		
		
			
		
		
			begin
		
		
			  if p_num is null then
		
		
			    return null;
		
		
			  end if; --转换数字为null时返回null
		
		
			
		
		
			  select to_char(nvl(substr(to_char(num_round),
		
		
			                            1,
		
		
			                            decode(instr(to_char(num_round), '.'),
		
		
			                                   0,
		
		
			                                   length(num_round),
		
		
			                                   instr(to_char(num_round), '.') - 1)),
		
		
			                     0))
		
		
			    into num_left
		
		
			    from dual; --取得小数点左边的数字
		
		
			  select substr(to_char(num_round),
		
		
			                decode(instr(to_char(num_round), '.'),
		
		
			                       0,
		
		
			                       length(num_round) + 1,
		
		
			                       instr(to_char(num_round), '.') + 1),
		
		
			                2)
		
		
			    into num_right
		
		
			    from dual; --取得小数点右边的数字
		
		
			
		
		
			  if length(num_left) > 16 then
		
		
			    return '**********';
		
		
			  end if; --数字整数部分超过16位时
		
		
			
		
		
			  --采用从低至高的算法,先处理小数点右边的数字
		
		
			  if length(num_right) = 2 then
		
		
			    if to_number(substr(num_right, 1, 1)) = 0 then
		
		
			      result := '零' ||
		
		
			                substr(str1, to_number(substr(num_right, 2, 1)) + 1, 1) || '分';
		
		
			    else
		
		
			      result := substr(str1, to_number(substr(num_right, 1, 1)) + 1, 1) || '角' ||
		
		
			                substr(str1, to_number(substr(num_right, 2, 1)) + 1, 1) || '分';
		
		
			    end if;
		
		
			  elsif length(num_right) = 1 then
		
		
			    result := substr(str1, to_number(substr(num_right, 1, 1)) + 1, 1) || '角整';
		
		
			  else
		
		
			    result := '整';
		
		
			  end if;
		
		
			  --再处理小数点左边的数字
		
		
			  for i in reverse 1 .. length(num_left) loop
		
		
			    --(从低至高)
		
		
			    num_count := num_count + 1; --当前数字位数
		
		
			    num_current := to_number(substr(num_left, i, 1)); --当前位上的数字
		
		
			    if num_current > 0 then
		
		
			      --当前位上数字不为0按正常处理
		
		
			      result := substr(str1, num_current + 1, 1) ||
		
		
			                substr(str2, num_count, 1) || result;
		
		
			    else
		
		
			      --当前位上数字为0时
		
		
			      if mod(num_count - 1, 4) = 0 then
		
		
			        --当前位是元、万或亿时
		
		
			        result := substr(str2, num_count, 1) || result;
		
		
			        num_pre := 0; --元、万,亿前不准加零
		
		
			      end if;
		
		
			      if num_pre > 0 or length(num_left) = 1 then
		
		
			        --上一位数字不为0或只有个位时
		
		
			        result := substr(str1, num_current + 1, 1) || result;
		
		
			      end if;
		
		
			    end if;
		
		
			    num_pre := num_current;
		
		
			  end loop;
		
		
			
		
		
			  if p_num < 0 then
		
		
			    --转换数字是负数时
		
		
			    result := '负' || result;
		
		
			  end if;
		
		
			
		
		
			  return Result;
		
		
			
		
		
			exception
		
		
			  when others then
		
		
			    raise_application_error(-20001, '数字转换大写出现错误!' || sqlerrm);
		
		
			end;