您好,登录后才能下订单哦!
密码登录
登录注册
点击 登录注册 即表示同意《亿速云用户服务条款》
这篇文章主要介绍了Django如何实现翻页,具有一定借鉴价值,感兴趣的朋友可以参考下,希望大家阅读完这篇文章之后大有收获,下面让小编带着大家一起了解一下。
Django提供了翻页器。用Django的Paginator类实现
ApiTest/apiviews.py
每行都加了注释,希望有助于理解。
from django.shortcuts import render from ApiTest.models import ApiTest from django.contrib.auth.decorators import login_required from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger, InvalidPage @login_required def api_test_manage(request): username = request.session.get('user', '') # 获取所有接口测试数据 apitest_list = ApiTest.objects.all().order_by('id') # 生成Paginator对象对数据分页,每页显示10条数据 paginator = Paginator(apitest_list,10) # 使用request.GET.get()函数获取url中的page参数的数值。默认第1页 page = request.GET.get('page', 1) # 把获取的当前页码数转换成整数类型 current_page = int(page) try: # 获取查询页数的接口数据列表,page()函数会判断page实参是否是有效数字。page()函数源码附在文章的最后 apitest_list = paginator.page(page) except PageNotAnInteger: apitest_list = paginator.page(1) except (EmptyPage, InvalidPage): # paginator.num_pages apitest_list = paginator.page(paginator.num_pages) return render(request, "apitest_manage.html", {'user': username, 'apitests': apitest_list})
在对应的html文件中加入此段代码即可。
<div class="container"> <ul class="pagination" id="pager"> {# 上一页链接 #} {% if apitests.has_previous %} <li class="previous"><a href="/apitest_manage/?page={{ apitests.previous_page_number }}" rel="external nofollow" >上一页</a></li> {% else %} <li class="previous disabled"><a href="#" rel="external nofollow" rel="external nofollow" >上一页</a></li> {% endif %} {# 中间数字显示 #} {% for num in apitests.paginator.page_range %} {% if num == currentPage %} <li class="item active"><a href="/apitest_manage/?page={{ num }}" rel="external nofollow" rel="external nofollow" >{{ num }}</a></li> {% else %} <li class="item"><a href="/apitest_manage/?page={{ num }}" rel="external nofollow" rel="external nofollow" >{{ num }}</a></li> {% endif %} {% endfor %} {# 下一页链接 #} {% if apitests.has_next %} {# 如果有下一页,则正常显示下一页链接 #} <li class="next"><a href="/apitest_manage/?page={{ apitests.next_page_number }}" rel="external nofollow" >下一页</a></li> {% else %} <li class="next disabled"><a href="#" rel="external nofollow" rel="external nofollow" >下一页</a></li> {% endif %} </ul> </div>
此类主要用在views文件
class Paginator: def __init__(self, object_list, per_page, orphans=0, allow_empty_first_page=True): self.object_list = object_list self._check_object_list_is_ordered() self.per_page = int(per_page) self.orphans = int(orphans) self.allow_empty_first_page = allow_empty_first_page def validate_number(self, number): """Validate the given 1-based page number.""" try: if isinstance(number, float) and not number.is_integer(): raise ValueError number = int(number) except (TypeError, ValueError): raise PageNotAnInteger(_('That page number is not an integer')) if number < 1: raise EmptyPage(_('That page number is less than 1')) if number > self.num_pages: if number == 1 and self.allow_empty_first_page: pass else: raise EmptyPage(_('That page contains no results')) return number def get_page(self, number): """ Return a valid page, even if the page argument isn't a number or isn't in range. """ try: number = self.validate_number(number) except PageNotAnInteger: number = 1 except EmptyPage: number = self.num_pages return self.page(number) def page(self, number): """Return a Page object for the given 1-based page number.""" number = self.validate_number(number) bottom = (number - 1) * self.per_page top = bottom + self.per_page if top + self.orphans >= self.count: top = self.count return self._get_page(self.object_list[bottom:top], number, self) def _get_page(self, *args, **kwargs): """ Return an instance of a single page. This hook can be used by subclasses to use an alternative to the standard :cls:`Page` object. """ return Page(*args, **kwargs) @cached_property def count(self): """Return the total number of objects, across all pages.""" c = getattr(self.object_list, 'count', None) if callable(c) and not inspect.isbuiltin(c) and method_has_no_args(c): return c() return len(self.object_list) @cached_property def num_pages(self): """Return the total number of pages.""" if self.count == 0 and not self.allow_empty_first_page: return 0 hits = max(1, self.count - self.orphans) return ceil(hits / self.per_page) @property def page_range(self): """ Return a 1-based range of pages for iterating through within a template for loop. """ return range(1, self.num_pages + 1) def _check_object_list_is_ordered(self): """ Warn if self.object_list is unordered (typically a QuerySet). """ ordered = getattr(self.object_list, 'ordered', None) if ordered is not None and not ordered: obj_list_repr = ( '{} {}'.format(self.object_list.model, self.object_list.__class__.__name__) if hasattr(self.object_list, 'model') else '{!r}'.format(self.object_list) ) warnings.warn( 'Pagination may yield inconsistent results with an unordered ' 'object_list: {}.'.format(obj_list_repr), UnorderedObjectListWarning, stacklevel=3 )
此类主要用在html文件
class Page(collections.abc.Sequence): def __init__(self, object_list, number, paginator): self.object_list = object_list self.number = number self.paginator = paginator def __repr__(self): return '<Page %s of %s>' % (self.number, self.paginator.num_pages) def __len__(self): return len(self.object_list) def __getitem__(self, index): if not isinstance(index, (int, slice)): raise TypeError( 'Page indices must be integers or slices, not %s.' % type(index).__name__ ) # The object_list is converted to a list so that if it was a QuerySet # it won't be a database hit per __getitem__. if not isinstance(self.object_list, list): self.object_list = list(self.object_list) return self.object_list[index] def has_next(self): return self.number < self.paginator.num_pages def has_previous(self): return self.number > 1 def has_other_pages(self): return self.has_previous() or self.has_next() def next_page_number(self): return self.paginator.validate_number(self.number + 1) def previous_page_number(self): return self.paginator.validate_number(self.number - 1) def start_index(self): """ Return the 1-based index of the first object on this page, relative to total objects in the paginator. """ # Special case, return zero if no items. if self.paginator.count == 0: return 0 return (self.paginator.per_page * (self.number - 1)) + 1 def end_index(self): """ Return the 1-based index of the last object on this page, relative to total objects found (hits). """ # Special case for the last page because there can be orphans. if self.number == self.paginator.num_pages: return self.paginator.count return self.number * self.paginator.per_page
感谢你能够认真阅读完这篇文章,希望小编分享的“Django如何实现翻页”这篇文章对大家有帮助,同时也希望大家多多支持亿速云,关注亿速云行业资讯频道,更多相关知识等着你来学习!
免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。