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Spark怎样实现推荐系统中的相似度算法，针对这个问题，这篇文章详细介绍了相对应的分析和解答，希望可以帮助更多想解决这个问题的小伙伴找到更简单易行的方法。
在推荐系统中，协同过滤算法是应用较多的，具体又主要划分为基于用户和基于物品的协同过滤算法，核心点就是基于"一个人"或"一件物品"，根据这个人或物品所具有的属性，比如对于人就是性别、年龄、工作、收入、喜好等，找出与这个人或物品相似的人或物，当然实际处理中参考的因子会复杂的多。
def euclidean2(v1: Vector, v2: Vector): Double = {require(v1.size == v2.size, s"SimilarityAlgorithms:Vector dimensions do not match: Dim(v1)=${v1.size} and Dim(v2)" +s"=${v2.size}.")val x = v1.toArrayval y = v2.toArrayeuclidean(x, y)}def euclidean(x: Array[Double], y: Array[Double]): Double = {require(x.length == y.length, s"SimilarityAlgorithms:Array length do not match: Len(x)=${x.length} and Len(y)" +s"=${y.length}.")math.sqrt(x.zip(y).map(p => p._1 - p._2).map(d => d * d).sum)}def euclidean(v1: Vector, v2: Vector): Double = {val sqdist = Vectors.sqdist(v1, v2)math.sqrt(sqdist)}
def pearsonCorrelationSimilarity(arr1: Array[Double], arr2: Array[Double]): Double = {require(arr1.length == arr2.length, s"SimilarityAlgorithms:Array length do not match: Len(x)=${arr1.length} and Len(y)" +s"=${arr2.length}.")val sum_vec1 = arr1.sumval sum_vec2 = arr2.sumval square_sum_vec1 = arr1.map(x => x * x).sumval square_sum_vec2 = arr2.map(x => x * x).sumval zipVec = arr1.zip(arr2)val product = zipVec.map(x => x._1 * x._2).sumval numerator = product - (sum_vec1 * sum_vec2 / arr1.length)val dominator = math.pow((square_sum_vec1 - math.pow(sum_vec1, 2) / arr1.length) * (square_sum_vec2 - math.pow(sum_vec2, 2) / arr2.length), 0.5)if (dominator == 0) Double.NaN else numerator / (dominator * 1.0)}
余弦相似度
/** jblas实现余弦相似度 */def cosineSimilarity(v1: DoubleMatrix, v2: DoubleMatrix): Double = {require(x.length == y.length, s"SimilarityAlgorithms:Array length do not match: Len(v1)=${x.length} and Len(v2)" +s"=${y.length}.")v1.dot(v2) / (v1.norm2() * v2.norm2())}def cosineSimilarity(v1: Vector, v2: Vector): Double = {require(v1.size == v2.size, s"SimilarityAlgorithms:Vector dimensions do not match: Dim(v1)=${v1.size} and Dim(v2)" +s"=${v2.size}.")val x = v1.toArrayval y = v2.toArraycosineSimilarity(x, y)}def cosineSimilarity(x: Array[Double], y: Array[Double]): Double = {require(x.length == y.length, s"SimilarityAlgorithms:Array length do not match: Len(x)=${x.length} and Len(y)" +s"=${y.length}.")val member = x.zip(y).map(d => d._1 * d._2).sumval temp1 = math.sqrt(x.map(math.pow(_, 2)).sum)val temp2 = math.sqrt(y.map(math.pow(_, 2)).sum)val denominator = temp1 * temp2if (denominator == 0) Double.NaN else member / (denominator * 1.0)}
修正余弦相似度
def adjustedCosineSimJblas(x: DoubleMatrix, y: DoubleMatrix): Double = {require(x.length == y.length, s"SimilarityAlgorithms:DoubleMatrix length do not match: Len(x)=${x.length} and Len(y)" +s"=${y.length}.")val avg = (x.sum() + y.sum()) / (x.length + y.length)val v1 = x.sub(avg)val v2 = y.sub(avg)v1.dot(v2) / (v1.norm2() * v2.norm2())}def adjustedCosineSimJblas(x: Array[Double], y: Array[Double]): Double = {require(x.length == y.length, s"SimilarityAlgorithms:Array length do not match: Len(x)=${x.length} and Len(y)" +s"=${y.length}.")val v1 = new DoubleMatrix(x)val v2 = new DoubleMatrix(y)adjustedCosineSimJblas(v1, v2)}def adjustedCosineSimilarity(v1: Vector, v2: Vector): Double = {require(v1.size == v2.size, s"SimilarityAlgorithms:Vector dimensions do not match: Dim(v1)=${v1.size} and Dim(v2)" +s"=${v2.size}.")val x = v1.toArrayval y = v2.toArrayadjustedCosineSimilarity(x, y)}def adjustedCosineSimilarity(x: Array[Double], y: Array[Double]): Double = {require(x.length == y.length, s"SimilarityAlgorithms:Array length do not match: Len(x)=${x.length} and Len(y)" +s"=${y.length}.")val avg = (x.sum + y.sum) / (x.length + y.length)val member = x.map(_ - avg).zip(y.map(_ - avg)).map(d => d._1 * d._2).sumval temp1 = math.sqrt(x.map(num => math.pow(num - avg, 2)).sum)val temp2 = math.sqrt(y.map(num => math.pow(num - avg, 2)).sum)val denominator = temp1 * temp2if (denominator == 0) Double.NaN else member / (denominator * 1.0)}
大家如果在实际业务处理中有相关需求，可以根据实际场景对上述代码进行优化或改造，当然很多算法框架提供的一些算法是对这些相似度算法的封装，底层还是依赖于这一套，也能帮助大家做更好的了解。比如Spark MLlib在KMeans算法实现中，底层对欧几里得距离的计算实现。
关于Spark怎样实现推荐系统中的相似度算法问题的解答就分享到这里了，希望以上内容可以对大家有一定的帮助，如果你还有很多疑惑没有解开，可以关注亿速云行业资讯频道了解更多相关知识。
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