python中如何使用urllib 和 json 模块

输入：

#!/usr/bin/python 

# Filename: yahoo_search.py 

import sys 

if sys.version_info[0] != 3: 

    sys.exit('This program needs Python 3.0') 

import jsonimport urllib, urllib.parse, urllib.request, urllib.response 

# Get your own APP ID at http://developer.yahoo.com/wsregapp/

YAHOO_APP_ID=jl22psvV34HELWhdfUJbfDQzlJ2B57KFS_qs4I8D0Wz5U5_yCI1Awv8.lBSfPhwr' 

SEARCH_BASE='http://search.yahooapis.com/WebSearchService/V1/webSearch'

class YahooSearchError(Exception): 

    pass 

# Taken from http://developer.yahoo.com/python/python-json.html 

def search(query, results=20, start=1, **kwargs): 

    kwargs.update({ 'appid': YAHOO_APP_ID, 

     'query': query, 'results': results,

     'start': start, 'output': 'json' 

     }) 

    url = SEARCH_BASE + '?' + urllib.parse.urlencode(kwargs) 

    result = json.load(urllib.request.urlopen(url)) 

    if 'Error' in result: 

        raise YahooSearchError(result['Error']) 

    return result['ResultSet'] 

query = input('What do you want to search for? ')

for result in search(query)['Result']: 

    print("{0} : {1}".format(result['Title'], result['Url']))

输出：