您好,登录后才能下订单哦!
密码登录
登录注册
点击 登录注册 即表示同意《亿速云用户服务条款》
这篇文章将为大家详细讲解有关java8中java.util.function.*pojo反射的示例分析,小编觉得挺实用的,因此分享给大家做个参考,希望大家阅读完这篇文章后可以有所收获。
写一个普通的POJO
public class City { private String name; private String code; public City() { } public City(String name, String code) { this.name = name; this.code = code; } public String getName() { return name; } public void setName(String name) { this.name = name; } public String getCode() { return code; } public void setCode(String code) { this.code = code; } }
传统的方式
// Use a constructor with parameters to create a City City sf = new City("San Francisco", "SF"); // Use a default constructor with no parameters to create a City City la = new City(); // Set the members using setters la.setName("Los Angeles"); la.setCode("LA");
新的getter访问方式
// Use the City's method references and assign them to functions Function<City, String> getNameFunction = City::getName; Function<City, String> getCodeFunction = City::getCode; System.out.println("The code for " + getNameFunction.apply(sf) + " is " + getCodeFunction.apply(sf)); -> The code for San Francisco is SF
新的setter访问方式
// Use the City's method references and assign them to biconsumers BiConsumer<City, String> setNameBiConsumer = City::setName; BiConsumer<City, String> setCodeBiConsumer = City::setCode; City ny = new City(); setNameBiConsumer.accept(ny, "New York"); setCodeBiConsumer.accept(ny, "NY");
访问 constructor 创建新实例
// Use the City's constructor method reference to create // a default constructor reference. Supplier<City> defaultConstructor = City::new; City sd = defaultConstructor.get(); sd.setName("San Diego"); sd.setCode("SD");
带参数的构建器
// Use the City's constructor method reference to create // a two-parameter constructor reference. BiFunction<String, String, City> twoParameterConstructor = City::new; City dc = twoParameterConstructor.apply("Washington, D. C.", "DC");
关于“java8中java.util.function.*pojo反射的示例分析”这篇文章就分享到这里了,希望以上内容可以对大家有一定的帮助,使各位可以学到更多知识,如果觉得文章不错,请把它分享出去让更多的人看到。
免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。