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话不多说,看代码和效果
/**
* 根据map中的某个key 去除List中重复的map
* @author shijing
* @param list
* @param mapKey
* @return
*/
public static List<Map<String, Object>> removeRepeatMapByKey(List<Map<String, Object>>
list, String mapKey){
if (CollectionUtils.isNullOrEmpty(list)) return null;
//把list中的数据转换成msp,去掉同一id值多余数据,保留查找到第一个id值对应的数据
List<Map<String, Object>> listMap = new ArrayList<>();
Map<String, Map> msp = new HashMap<>();
for(int i = list.size()-1 ; i>=0; i--){
Map map = list.get(i);
String id = (String)map.get(mapKey);
map.remove(mapKey);
msp.put(id, map);
}
//把msp再转换成list,就会得到根据某一字段去掉重复的数据的List<Map>
Set<String> mspKey = msp.keySet();
for(String key: mspKey){
Map newMap = msp.get(key);
newMap.put(mapKey, key);
listMap.add(newMap);
}
return listMap;
}
测试:
public static void main(String[] args) {
Map<String, Map> msp = new HashMap<String, Map>();
List<Map<String, Object>> list = new ArrayList<Map<String, Object>>();
List<Map<String, Object>> listMap = new ArrayList<Map<String,Object>>();
Map<String, Object> map1 = new HashMap<String, Object>();
map1.put("id", "1123");
map1.put("name", "张三");
Map<String, Object> map2 = new HashMap<String, Object>();
map2.put("id", "2");
map2.put("name", "李四");
Map<String, Object> map3 = new HashMap<String, Object>();
map3.put("id", "1123");
map3.put("name", "王五");
Map<String, Object> map4 = new HashMap<String, Object>();
map4.put("id", "3");
map4.put("name", "赵六");
list.add(map1);
list.add(map2);
list.add(map3);
list.add(map4);
System.out.println("初始数据:" + list.toString());
System.out.println("去重之后:" + removeRepeatMapByKey(list,"id"));
}
结果:
初始数据:[{name=张三, id=1123}, {name=李四, id=2}, {name=王五, id=1123}, {name=赵六, id=3}]
去重之后:[{name=李四, id=2}, {name=赵六, id=3}, {name=张三, id=1123}]
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