在C语言编程中,使用current
指针时需要注意以下几点:
int *current = NULL;
int *current = (int *)malloc(sizeof(int));
if (current != NULL) {
*current = 42;
} else {
printf("Error: current is a NULL pointer.\n");
}
free(current);
current = NULL;
int arr[] = {1, 2, 3, 4, 5};
int *current = arr;
printf("%d\n", *(current + 2)); // 输出3,因为current + 2指向arr[2]
int *current = NULL;
float *wrong_type = (float *)current; // 错误的类型转换
遵循这些注意事项,可以确保在C语言编程中正确、安全地使用current
指针。