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这篇文章将为大家详细讲解有关如何使用python实现Virginia无密钥解密,小编觉得挺实用的,因此分享给大家做个参考,希望大家阅读完这篇文章后可以有所收获。
加密
virginia加密是一种多表替换加密方法,通过这种方法,可以有效的解决单表替换中无法应对的字母频度攻击。这种加密方法最重要的就是选取合适的密钥,一旦密钥被公开,保密性也就无从谈起。结合virginia加密原理,给出使用python实现的代码
plainText = "whenigotthethemeithoughtofgooglesartificialintelligencealphagothisprogramoverthebestofhumanplayeriwanttoaskwhenscienceandtechnologycontinuetodevelopwehumanbeingswillbewhatpositionweshouldrealizethatthedevelopmentofscienceandtechnologyisirreversibleanditconstituteaprimaryprductiveforcebutmanmustkeeppacewiththetimestoenhancetheablitytocontrol" # 密文 alphabet = "abcdefghijklmnopqrstuvwxyz" # 26个字母 cipherText = ""; key = "helloworld" # 密钥 keyLen = len(key) plainTextLen = len(plainText) j = 0 for i in range(0,plainTextLen): j = i%keyLen keyNum = alphabet.index(key[j]) plainNum = alphabet.index(plainText[i]) plainTemp = alphabet[(keyNum*plainNum)%26] # 密钥对明文作用 cipherText += plainTemp print(cipherText)
解密
重点谈谈解密部分。这里的解密主要分为获取密钥长度,根据密钥长度获取密钥,根据密钥获取明文三个部分。
获取密钥长度
使用暴力破解密钥长度的方法,循环遍历可能的密钥长度。每次循环中,记录在这种密钥长度下重复相隔密钥长度密文的次数,从理论上来讲,次数最多的那个密钥长度,最有可能正确。当密文长度足够长时,正确的可能性很高。给出获取密钥长度的python函数代码:
def getKeyLen(cipherText): # 获取密钥长度 keylength = 1 maxCount = 0 for step in range(3,18): # 循环密钥长度 count = 0 for i in range(step,len(cipherText)-step): if cipherText[i] == cipherText[i+step]: count += 1 if count>maxCount: # 每次保存最大次数的密钥长度 maxCount = count keylength = step return keylength # 返回密钥长度
获取密钥
当已经获取密钥长度之后,我们可以通过分组将相同密钥作用下的密文进行分组,在每一组中,都是一个简单的单表替换加密。在这种情况下,我们通过重合指数法破解密钥,给出获取密钥部分的python函数代码:
def getKey(text,length): # 获取密钥 key = [] # 定义空白列表用来存密钥 alphaRate =[0.08167,0.01492,0.02782,0.04253,0.12705,0.02228,0.02015,0.06094,0.06996,0.00153,0.00772,0.04025,0.02406,0.06749,0.07507,0.01929,0.0009,0.05987,0.06327,0.09056,0.02758,0.00978,0.02360,0.0015,0.01974,0.00074] matrix =textToList(text,length) for i in range(length): w = [row[i] for row in matrix] #获取每组密文 li = countList(w) powLi = [] #算乘积 for j in range(26): Sum = 0.0 for k in range(26): Sum += alphaRate[k]*li[k] powLi.append(Sum) li = li[1:]+li[:1]#循环移位 Abs = 100 ch = '' for j in range(len(powLi)): if abs(powLi[j] -0.065546)<Abs: # 找出最接近英文字母重合指数的项 Abs = abs(powLi[j] -0.065546) # 保存最接近的距离,作为下次比较的基准 ch = chr(j+97) key.append(ch) return key
破解明文
在已知密钥和明文的基础上,我们很容易就可以得到明文,给出python代码:
def virginiaCrack(cipherText): # 解密函数 length = getKeyLen(cipherText) #得到密钥长度 key = getKey(cipherText,length) #找到密钥 keyStr = '' for k in key: keyStr+=k print('the Key is:',keyStr) plainText = '' index = 0 for ch in cipherText: c = chr((ord(ch)-ord(key[index%length]))%26+97) plainText += c index+=1 return plainText # 返回明文
代码
这是解密部分的全部代码,注意需要自己添加密文文件的位置
def virginiaCrack(cipherText): # 解密函数 length = getKeyLen(cipherText) #得到密钥长度 key = getKey(cipherText,length) #找到密钥 keyStr = '' for k in key: keyStr+=k print('the key:',keyStr) plainText = '' index = 0 for ch in cipherText: c = chr((ord(ch)-ord(key[index%length]))%26+97) plainText += c index+=1 return plainText def openfile(fileName): # 读文件 file = open(fileName,'r') text = file.read() file.close(); text = text.replace('\n','') return text def getKeyLen(cipherText): # 获取密钥长度 keylength = 1 maxCount = 0 for step in range(3,18): # 循环密钥长度 count = 0 for i in range(step,len(cipherText)-step): if cipherText[i] == cipherText[i+step]: count += 1 if count>maxCount: maxCount = count keylength = step return keylength def getKey(text,length): # 获取密钥 key = [] # 定义空白列表用来存密钥 alphaRate =[0.08167,0.01492,0.02782,0.04253,0.12705,0.02228,0.02015,0.06094,0.06996,0.00153,0.00772,0.04025,0.02406,0.06749,0.07507,0.01929,0.0009,0.05987,0.06327,0.09056,0.02758,0.00978,0.02360,0.0015,0.01974,0.00074] matrix =textToList(text,length) for i in range(length): w = [row[i] for row in matrix] #获取每组密文 li = countList(w) powLi = [] #算乘积 for j in range(26): Sum = 0.0 for k in range(26): Sum += alphaRate[k]*li[k] powLi.append(Sum) li = li[1:]+li[:1]#循环移位 Abs = 100 ch = '' for j in range(len(powLi)): if abs(powLi[j] -0.065546)<Abs: # 找出最接近英文字母重合指数的项 Abs = abs(powLi[j] -0.065546) # 保存最接近的距离,作为下次比较的基准 ch = chr(j+97) key.append(ch) return key def countList(lis): # 统计字母频度 li = [] alphabet = [chr(i) for i in range(97,123)] for c in alphabet: count = 0 for ch in lis: if ch == c: count+=1 li.append(count/len(lis)) return li def textToList(text,length): # 根据密钥长度将密文分组 textMatrix = [] row = [] index = 0 for ch in text: row.append(ch) index += 1 if index % length ==0: textMatrix.append(row) row = [] return textMatrix if __name__ == '__main__': cipherText = openfile(r'') # 这里要根据文档目录的不同而改变 plainText= virginiaCrack(cipherText) print('the plainText:\n',plainText)
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