微信跳一跳自动运行python脚本

发布时间:2020-10-10 21:06:24 作者:qq71413
来源:脚本之家 阅读:295

本文实例为大家分享了微信小程序跳一跳自动运行脚本,供大家参考,具体内容如下

1、压缩包带了adb等必须工具,配置一下环境变量即可

2、Python 直接运行即可 (Python3.6)

代码:

wechat_jump_auto.py

# coding: utf-8
'''
# === 思路 ===
# 核心:每次落稳之后截图,根据截图算出棋子的坐标和下一个块顶面的中点坐标,
# 根据两个点的距离乘以一个时间系数获得长按的时间
# 识别棋子:靠棋子的颜色来识别位置,通过截图发现最下面一行大概是一条直线,就从上往下一行一行遍历,
# 比较颜色(颜色用了一个区间来比较)找到最下面的那一行的所有点,然后求个中点,
# 求好之后再让 Y 轴坐标减小棋子底盘的一半高度从而得到中心点的坐标
# 识别棋盘:靠底色和方块的色差来做,从分数之下的位置开始,一行一行扫描,由于圆形的块最顶上是一条线,
# 方形的上面大概是一个点,所以就用类似识别棋子的做法多识别了几个点求中点,
# 这时候得到了块中点的 X 轴坐标,这时候假设现在棋子在当前块的中心,
# 根据一个通过截图获取的固定的角度来推出中点的 Y 坐标
# 最后:根据两点的坐标算距离乘以系数来获取长按时间(似乎可以直接用 X 轴距离)
'''
import os
import sys
import subprocess
import time
import math
from PIL import Image
import random
from six.moves import input
import debug, config
import numpy as np



VERSION = "1.1.1"


debug_switch = False # debug 开关,需要调试的时候请改为:True
config = config.open_accordant_config()

# Magic Number,不设置可能无法正常执行,请根据具体截图从上到下按需设置,设置保存在 config 文件夹中
under_game_score_y = config['under_game_score_y']
press_coefficient = config['press_coefficient'] # 长按的时间系数,请自己根据实际情况调节
piece_base_height_1_2 = config['piece_base_height_1_2'] # 二分之一的棋子底座高度,可能要调节
piece_body_width = config['piece_body_width'] # 棋子的宽度,比截图中量到的稍微大一点比较安全,可能要调节


screenshot_way = 2


def pull_screenshot():
 '''
 新的方法请根据效率及适用性由高到低排序
 '''
 global screenshot_way
 if screenshot_way == 2 or screenshot_way == 1:
 process = subprocess.Popen('adb shell screencap -p', shell=True, stdout=subprocess.PIPE)
 screenshot = process.stdout.read()
 if screenshot_way == 2:
 binary_screenshot = screenshot.replace(b'\r\n', b'\n')
 else:
 binary_screenshot = screenshot.replace(b'\r\r\n', b'\n')
 f = open('autojump.png', 'wb')
 f.write(binary_screenshot)
 f.close()
 elif screenshot_way == 0:
 os.system('adb shell screencap -p /sdcard/autojump.png')
 os.system('adb pull /sdcard/autojump.png .')


def set_button_position(im):
 '''
 将 swipe 设置为 `再来一局` 按钮的位置
 '''
 global swipe_x1, swipe_y1, swipe_x2, swipe_y2
 w, h = im.size
 left = int(w / 2)
 top = int(1584 * (h / 1920.0))
 left = int(random.uniform(left-50, left+50))
 top = int(random.uniform(top-10, top+10)) # 随机防 ban
 swipe_x1, swipe_y1, swipe_x2, swipe_y2 = left, top, left, top


def jump(distance):
 '''
 跳跃一定的距离
 '''
 press_time = distance * press_coefficient
 press_time = max(press_time, 200) # 设置 200ms 是最小的按压时间
 press_time = int(press_time)
 cmd = 'adb shell input swipe {x1} {y1} {x2} {y2} {duration}'.format(
 x1=swipe_x1,
 y1=swipe_y1,
 x2=swipe_x2,
 y2=swipe_y2,
 duration=press_time
 )
 print(cmd)
 os.system(cmd)
 return press_time


def find_piece_and_board(im):
 '''
 寻找关键坐标
 '''
 w, h = im.size

 piece_x_sum = 0
 piece_x_c = 0
 piece_y_max = 0
 board_x = 0
 board_y = 0
 scan_x_border = int(w / 8) # 扫描棋子时的左右边界
 scan_start_y = 0 # 扫描的起始 y 坐标
 im_pixel = im.load()
 # 以 50px 步长,尝试探测 scan_start_y
 for i in range(int(h / 3), int(h*2 / 3), 50):
 last_pixel = im_pixel[0, i]
 for j in range(1, w):
 pixel = im_pixel[j, i]
 # 不是纯色的线,则记录 scan_start_y 的值,准备跳出循环
 if pixel[0] != last_pixel[0] or pixel[1] != last_pixel[1] or pixel[2] != last_pixel[2]:
 scan_start_y = i - 50
 break
 if scan_start_y:
 break
 print('scan_start_y: {}'.format(scan_start_y))

 # 从 scan_start_y 开始往下扫描,棋子应位于屏幕上半部分,这里暂定不超过 2/3
 for i in range(scan_start_y, int(h * 2 / 3)):
 for j in range(scan_x_border, w - scan_x_border): # 横坐标方面也减少了一部分扫描开销
 pixel = im_pixel[j, i]
 # 根据棋子的最低行的颜色判断,找最后一行那些点的平均值,这个颜色这样应该 OK,暂时不提出来
 if (50 < pixel[0] < 60) and (53 < pixel[1] < 63) and (95 < pixel[2] < 110):
 piece_x_sum += j
 piece_x_c += 1
 piece_y_max = max(i, piece_y_max)

 if not all((piece_x_sum, piece_x_c)):
 return 0, 0, 0, 0
 piece_x = int(piece_x_sum / piece_x_c)
 piece_y = piece_y_max - piece_base_height_1_2 # 上移棋子底盘高度的一半

 # 限制棋盘扫描的横坐标,避免音符 bug
 if piece_x < w/2:
 board_x_start = piece_x
 board_x_end = w
 else:
 board_x_start = 0
 board_x_end = piece_x

 for i in range(int(h / 3), int(h * 2 / 3)):
 last_pixel = im_pixel[0, i]
 if board_x or board_y:
 break
 board_x_sum = 0
 board_x_c = 0

 for j in range(int(board_x_start), int(board_x_end)):
 pixel = im_pixel[j, i]
 # 修掉脑袋比下一个小格子还高的情况的 bug
 if abs(j - piece_x) < piece_body_width:
 continue

 # 修掉圆顶的时候一条线导致的小 bug,这个颜色判断应该 OK,暂时不提出来
 if abs(pixel[0] - last_pixel[0]) + abs(pixel[1] - last_pixel[1]) + abs(pixel[2] - last_pixel[2]) > 10:
 board_x_sum += j
 board_x_c += 1
 if board_x_sum:
 board_x = board_x_sum / board_x_c
 last_pixel = im_pixel[board_x, i]

 # 从上顶点往下 +274 的位置开始向上找颜色与上顶点一样的点,为下顶点
 # 该方法对所有纯色平面和部分非纯色平面有效,对高尔夫草坪面、木纹桌面、药瓶和非菱形的碟机(好像是)会判断错误
 for k in range(i+274, i, -1): # 274 取开局时最大的方块的上下顶点距离
 pixel = im_pixel[board_x, k]
 if abs(pixel[0] - last_pixel[0]) + abs(pixel[1] - last_pixel[1]) + abs(pixel[2] - last_pixel[2]) < 10:
 break
 board_y = int((i+k) / 2)

 # 如果上一跳命中中间,则下个目标中心会出现 r245 g245 b245 的点,利用这个属性弥补上一段代码可能存在的判断错误
 # 若上一跳由于某种原因没有跳到正中间,而下一跳恰好有无法正确识别花纹,则有可能游戏失败,由于花纹面积通常比较大,失败概率较低
 for l in range(i, i+200):
 pixel = im_pixel[board_x, l]
 if abs(pixel[0] - 245) + abs(pixel[1] - 245) + abs(pixel[2] - 245) == 0:
 board_y = l+10
 break

 if not all((board_x, board_y)):
 return 0, 0, 0, 0

 return piece_x, piece_y, board_x, board_y


def check_screenshot():
 '''
 检查获取截图的方式
 '''
 global screenshot_way
 if os.path.isfile('autojump.png'):
 os.remove('autojump.png')
 if (screenshot_way < 0):
 print('暂不支持当前设备')
 sys.exit()
 pull_screenshot()
 try:
 Image.open('./autojump.png').load()
 print('采用方式 {} 获取截图'.format(screenshot_way))
 except Exception:
 screenshot_way -= 1
 check_screenshot()


def yes_or_no(prompt, true_value='y', false_value='n', default=True):
 default_value = true_value if default else false_value
 prompt = '%s %s/%s [%s]: ' % (prompt, true_value, false_value, default_value)
 i = input(prompt)
 if not i:
 return default
 while True:
 if i == true_value:
 return True
 elif i == false_value:
 return False
 prompt = 'Please input %s or %s: ' % (true_value, false_value)
 i = input(prompt)


def main():
 '''
 主函数
 '''
 op = yes_or_no('请确保手机打开了 ADB 并连接了电脑,然后打开跳一跳并【开始游戏】后再用本程序,确定开始?')
 if not op:
 print('bye')
 return
 print('程序版本号:{}'.format(VERSION))
 debug.dump_device_info()
 check_screenshot()

 i, next_rest, next_rest_time = 0, random.randrange(3, 10), random.randrange(5, 10)
 while True:
 pull_screenshot()
 im = Image.open('./autojump.png')
 # 获取棋子和 board 的位置
 piece_x, piece_y, board_x, board_y = find_piece_and_board(im)
 ts = int(time.time())
 print(ts, piece_x, piece_y, board_x, board_y)
 set_button_position(im)
 jump(math.sqrt((board_x - piece_x) ** 2 + (board_y - piece_y) ** 2))
 if debug_switch:
 debug.save_debug_screenshot(ts, im, piece_x, piece_y, board_x, board_y)
 debug.backup_screenshot(ts)
 i += 1
 if i == next_rest:
 print('已经连续打了 {} 下,休息 {}s'.format(i, next_rest_time))
 for j in range(next_rest_time):
 sys.stdout.write('\r程序将在 {}s 后继续'.format(next_rest_time - j))
 sys.stdout.flush()
 time.sleep(2)
 print('\n继续')
 i, next_rest, next_rest_time = 0, random.randrange(30, 100), random.randrange(10, 60)
 time.sleep(np.random.uniform(0.6,0.9)) # 为了保证截图的时候应落稳了,多延迟一会儿,随机值防 ban


if __name__ == '__main__':
 main()

simple.py

# -*- coding: utf-8 -*-

import numpy as np
import cv2
import os
import time
import re

# 屏幕截图
def pull_screenshot(path):
 os.system('adb shell screencap -p /sdcard/%s' % path)
 os.system('adb pull /sdcard/%s .' % path)

# 根据x距离跳跃
def jump(distance, alpha):
 press_time = max(int(distance * alpha), 200)

 cmd = 'adb shell input swipe {} {} {} {} {}'.format(bx1, by1, bx2, by2, press_time)
 os.system(cmd)

screenshot = 'screenshot.png'
alpha = 0
bx1, by1, bx2, by2 = 0, 0, 0, 0
chess_x = 0
target_x = 0

fix = 1.6667

# 检查分辨率是否是960x540
size_str = os.popen('adb shell wm size').read()
if size_str:
 m = re.search(r'(\d+)x(\d+)', size_str)
 if m:
 hxw = "{height}x{width}".format(height=m.group(2), width=m.group(1))
 if hxw == "960x540":
 fix = 3.16

while True:
 pull_screenshot(screenshot)
 image_np = cv2.imread(screenshot)
 image_np = cv2.cvtColor(image_np, cv2.COLOR_BGR2RGB)
 gray = cv2.Canny(image_np, 20, 80)

 HEIGHT = image_np.shape[0]
 WIDTH = image_np.shape[1]

 bx1 = WIDTH / 2
 bx2 = WIDTH / 2
 by1 = HEIGHT * 0.785
 by2 = HEIGHT * 0.785
 alpha = WIDTH * fix

 # 获取棋子x坐标
 linemax = []
 for i in range(int(HEIGHT * 0.4), int(HEIGHT * 0.6)):
 line = []
 for j in range(int(WIDTH * 0.15), int(WIDTH * 0.85)):
 if image_np[i, j, 0] > 40 and image_np[i, j, 0] < 70 and image_np[i, j, 1] > 40 and image_np[i, j, 1] < 70 and image_np[i, j, 2] > 60 and image_np[i, j, 2] < 110:
 gray[i, j] = 255
 if len(line) > 0 and j - line[-1] > 1:
 break
 else:
 line.append(j)

 if len(line) > 5 and len(line) > len(linemax):
 linemax = line
 if len(linemax) > 20 and len(line) == 0:
 break

 chess_x = int(np.mean(linemax))

 # 获取目标x坐标
 for i in range(int(HEIGHT * 0.3), int(HEIGHT * 0.5)):
 flag = False
 for j in range(WIDTH):
 # 超过朋友时棋子上方的图案
 if np.abs(j - chess_x) < len(linemax):
 continue
 if not gray[i, j] == 0:
 target_x = j
 flag = True
 break
 if flag:
 break

 # 修改检测图
 gray[:, chess_x] = 255
 gray[:, target_x] = 255
 # 保存检测图
 cv2.imwrite('detection.png', gray)

 print(chess_x, target_x)
 jump(float(np.abs(chess_x - target_x)) / WIDTH, alpha)

 # 等棋子落稳
 time.sleep(np.random.random() + 1)

下载:微信小程序跳一跳自动运行脚本

更多内容大家可以参考专题《微信跳一跳》进行学习。

更多关于python安装教程的文章请参考《python各版本安装教程》

更多精彩书单,请点击python编程必备书单

领取干货:零基础入门学习python视频教程

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持亿速云。

推荐阅读:
  1. python微信跳一跳系列之如何实现自动计算跳一跳距离
  2. 微信跳一跳python自动代码解读的示例分析

免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。

python 跳一跳

上一篇:一次围绕setTimeout的前端面试经验分享

下一篇:Python3 实现串口两进程同时读写

相关阅读

您好,登录后才能下订单哦!

密码登录
登录注册
其他方式登录
点击 登录注册 即表示同意《亿速云用户服务条款》