java如何实现纸牌游戏之小猫钓鱼算法

import java.util.LinkedList;
import java.util.Scanner;
import java.util.Stack;
 
public class Main {
 public static void main(String[] args) {
 Scanner scanner = new Scanner(System.in);
 LinkedList<Integer> a = new LinkedList<Integer>();//A手中的牌
 LinkedList<Integer> b = new LinkedList<Integer>();//B手中的牌
 Stack<Integer> stack = new Stack<>();//记录桌面上的牌
 int[] book = new int[10];//用来标记哪些牌已经在桌上
 int n,t,s;
 for(int i = 0; i < 10; i++){
 book[i] = 0;
 }
 System.out.println("输入手中牌的个数");
 n = scanner.nextInt();
 System.out.println("输入A君手中牌的大小");
 for(int i = 1; i<=n; i++){
 a.addLast(scanner.nextInt());
 }
 System.out.println("输入B君手中牌的大小");
 for(int i = 1; i<=n; i++){
 b.addLast(scanner.nextInt());
 }
 System.out.println("输入完毕开始游戏");
 while (!a.isEmpty() && !b.isEmpty()) {//当有人手中没牌游戏结束
 t = a.removeFirst();
 if (book[t] == 0) {//A没有赢
 stack.push(t);//桌面上加一张牌
 book[t] = 1;//记录桌面上已经有这张牌了
 }else {//A赢了
 a.addLast(t);//将打出的牌到到末尾
 while (!stack.peek().equals(t)) {//将桌面上的牌按顺序放到A的末尾
 s = stack.pop();
 a.addLast(s);
 book[s] = 0;
 }
 }
 
 //同上B取出牌
 t = b.removeFirst();
 if (book[t] == 0) {
 stack.push(t);
 book[t] = 1;
 } else {
 b.addLast(t);
 while (!stack.peek().equals(t)) {
 s = stack.pop();
 b.addLast(s);
 book[s]= 0;
 }
 }
 }
 
 if (!a.isEmpty()) {//A胜利
 System.out.println("A君胜利！A手中的牌是");
 while (!a.isEmpty()) {
 System.out.print(a.removeFirst()+ " ");
 }
 System.out.println();
 if (!stack.isEmpty()) {//桌面上有牌
 System.out.println("桌面上的牌是");
 for (Integer x : stack) { 
 System.out.print(x + " "); 
  } 
 } else {
 System.out.println("桌面没有牌了");
 }
 } else {//B胜利
 System.out.println("B君胜利！B手中的牌是");
 while (!b.isEmpty()) {
 System.out.print(b.removeFirst()+ " ");
 }
 System.out.println();
 if (!stack.isEmpty()) {//桌面上有牌
 System.out.println("桌面上的牌是");
 for (Integer x : stack) { 
 System.out.print(x + " "); 
  } 
 } else {
 System.out.println("桌面没有牌了");
 }
 }
 return;//结束
 }
}