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本篇内容介绍了“如何用C语言代码实现扫雷游戏”的有关知识,在实际案例的操作过程中,不少人都会遇到这样的困境,接下来就让小编带领大家学习一下如何处理这些情况吧!希望大家仔细阅读,能够学有所成!
代码如下:
#include<stdio.h>#include<stdlib.h>#include<time.h>#define ROW 9#define COL 9#define ROWS ROW+2#define COLS COL+2#define EASY_COUNT 10//函数声明void ChushiBoard(char board[ROWS][COLS],int rows,int cols,char set);void Dayinboard(char board[ROWS][COLS], int row, int col);void BuzhiBoard(char mine[ROWS][COLS], int row, int col);void CaoleiBoard(char mine[ROWS][COLS],char show[ROWS][COLS],int row,int col);void menu(){ printf("*****************************************\n"); printf("*****************************************\n"); printf("**** 输入1开始游戏 输入0退出游戏 *****\n"); printf("*****************************************\n"); printf("*****************************************\n\n\n");}void game(){ char mine[ROWS][COLS];//存放雷 char show[ROWS][COLS];//显示排查出来的雷 //初始化 ChushiBoard(mine, ROWS, COLS,'0');//'0' ChushiBoard(show, ROWS, COLS,'*');//'*' //布置雷 BuzhiBoard(mine,ROW,COL); //Dayinboard(mine, ROW, COL); //打印棋盘 Dayinboard(show, ROW, COL); //扫雷 CaoleiBoard(mine,show,ROW,COL);}void test(){ int input = 0; do { menu(); printf("请输入:>"); scanf("%d", &input); switch (input) { case 1: game(); break; case 0: printf("退出游戏\n\n"); break; default: printf("输入错误,重新输入\n\n"); break; } } while (input);}int main(){ test(); system("pause"); return 0;}void ChushiBoard(char board[ROWS][COLS], int rows, int cols,char set){ int i = 0; int j = 0; for (i = 0; i < rows; i++) { for (j = 0; j < cols; j++) { board[i][j] = set; } }}void Dayinboard(char board[ROWS][COLS], int row, int col){ int i = 0; int j = 0; printf("------------------------------\n"); for (i = 0; i <= col; i++) { printf(" %d ", i); } printf("\n"); for (i = 1; i <= row; i++) { printf(" %d ", i); for (j = 1; j <= col; j++) { printf(" %c ", board[i][j]); } printf("\n"); } printf("------------------------------\n");}void BuzhiBoard(char mine[ROWS][COLS], int row, int col){ int count = EASY_COUNT; while (count) { int x = rand()%row+1; int y = rand()%col+1; if (mine[x][y] == '0') { mine[x][y] = '1'; count--; } }}static int GetMineCount(char mine[ROWS][COLS], int x, int y){ return mine[x - 1][y] + mine[x - 1][y - 1] + mine[x][y - 1] + mine[x + 1][y - 1] + mine[x + 1][y] + mine[x + 1][y + 1] + mine[x][y + 1] + mine[x - 1][y + 1] - 8 * '0';}void CaoleiBoard(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col){ int x = 0; int y = 0; int win = 0; while (win<row*col-EASY_COUNT) { printf("请输入要排查的坐标(格式:X空格X回车):>"); scanf("%d%d", &x, &y); if (x >= 1 && x <= 9 && y >= 1 && y <= 9) { if (mine[x][y] == '1') { printf(" 很遗憾,你被炸死了!!!\n"); Dayinboard(mine, row, col); break; } else { int count = GetMineCount(mine,x,y); show[x][y] = count+'0'; Dayinboard(show, row, col); win++; } } else { printf("输入的坐标非法\n"); } } if (win == row*col - EASY_COUNT) { printf(" 恭喜你,你排雷成功了!!!\n"); }}
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