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# MySQL中TIMESTAMPDIFF的示例分析
## 一、TIMESTAMPDIFF函数概述
### 1.1 基本定义
`TIMESTAMPDIFF()`是MySQL中用于计算两个时间点之间差值的日期时间函数,返回结果为整数。与`DATEDIFF`仅计算天数不同,它可以灵活计算年、月、日、小时等不同单位的时间差。
```sql
TIMESTAMPDIFF(unit, datetime_expr1, datetime_expr2)
单位 | 说明 | 边界值处理方式 |
---|---|---|
YEAR | 整年数 | 忽略月日时分秒 |
QUARTER | 季度数(1-4) | 3个月为一个季度 |
MONTH | 整月数 | 不足整月不计 |
WEEK | 整周数 | 按7天计算 |
DAY | 整天数 | 不足24小时不计 |
HOUR | 整小时数 | 不足60分钟不计 |
MINUTE | 整分钟数 | 不足60秒不计 |
SECOND | 秒数 | 精确计算 |
@@GLOBAL.week_start
设置不同而变化SELECT
name,
TIMESTAMPDIFF(YEAR, birth_date, CURDATE()) AS age
FROM employees;
结果示例:
+--------+------+
| name | age |
+--------+------+
| 张三 | 28 |
| 李四 | 35 |
+--------+------+
SELECT
order_id,
TIMESTAMPDIFF(MONTH, order_date, delivery_date) AS months_taken
FROM orders
WHERE status = 'delivered';
SELECT
ticket_id,
TIMESTAMPDIFF(HOUR, create_time, resolve_time) AS resolution_hours,
TIMESTAMPDIFF(MINUTE, create_time, resolve_time) % 60 AS remaining_minutes
FROM support_tickets;
SELECT
TIMESTAMPDIFF(MONTH, u.register_date, a.access_date) AS month_diff,
COUNT(DISTINCT u.user_id) AS retained_users
FROM users u
JOIN access_logs a ON u.user_id = a.user_id
GROUP BY month_diff;
SELECT
project_id,
TIMESTAMPDIFF(DAY, start_date, end_date) -
(FLOOR(TIMESTAMPDIFF(DAY, start_date, end_date)/7)*2) -
(IF(DAYOFWEEK(start_date)=1,1,0)) -
(IF(DAYOFWEEK(end_date)=7,1,0)) AS work_days
FROM projects;
SELECT
room_id,
COUNT(*) OVER (PARTITION BY room_id) AS overlapping_bookings
FROM reservations
WHERE TIMESTAMPDIFF(HOUR, check_in, '2023-12-25 14:00:00') > 0
AND TIMESTAMPDIFF(HOUR, '2023-12-24 10:00:00', check_out) > 0;
-- 2000-02-29到2001-03-01的年份差
SELECT TIMESTAMPDIFF(YEAR, '2000-02-29', '2001-03-01'); -- 返回1
-- 1月31日到2月28日的月份差
SELECT TIMESTAMPDIFF(MONTH, '2023-01-31', '2023-02-28'); -- 返回0
SELECT TIMESTAMPDIFF(MONTH, '2023-01-31', '2023-03-01'); -- 返回1
-- 时间戳自动转换为datetime类型
SELECT TIMESTAMPDIFF(
HOUR,
'2023-01-01',
FROM_UNIXTIME(1672570800)
);
TIMESTAMPDIFF
计算字段建立函数索引:ALTER TABLE orders ADD INDEX idx_delivery_days ((TIMESTAMPDIFF(DAY, order_date, delivery_date)));
-- 低效写法
SELECT * FROM logs
WHERE TIMESTAMPDIFF(HOUR, create_time, NOW()) < 24;
-- 优化写法
SELECT * FROM logs
WHERE create_time > DATE_SUB(NOW(), INTERVAL 1 DAY);
-- 使用变量减少重复计算
SET @current_date = CURDATE();
SELECT
user_id,
TIMESTAMPDIFF(DAY, last_login, @current_date) AS days_inactive
FROM users;
-- 计算天差
SELECT
DATEDIFF('2023-12-31 23:59:59', '2023-12-30 00:00:01'), -- 返回1
TIMESTAMPDIFF(DAY, '2023-12-30 00:00:01', '2023-12-31 23:59:59'); -- 返回1
-- 计算小时差
SELECT
TIMESTAMPDIFF(HOUR, '2023-12-30 00:00:01', '2023-12-31 23:59:59'), -- 返回47
(UNIX_TIMESTAMP('2023-12-31 23:59:59') -
UNIX_TIMESTAMP('2023-12-30 00:00:01'))/3600; -- 返回47.999...
-- 月份差计算(格式要求不同)
SELECT
PERIOD_DIFF(202312, 202301), -- 返回11
TIMESTAMPDIFF(MONTH, '2023-01-01', '2023-12-31'); -- 返回11
-- 显式转换时区
SELECT TIMESTAMPDIFF(
HOUR,
CONVERT_TZ('2023-01-01 08:00:00', '+00:00', @@session.time_zone),
CONVERT_TZ('2023-01-02 09:00:00', '+08:00', @@session.time_zone)
);
-- 使用IFNULL处理空值
SELECT
order_id,
TIMESTAMPDIFF(DAY, order_date, IFNULL(ship_date, CURDATE())) AS days_pending
FROM orders;
-- 结合TIMESTAMPDIFF和TIMEDIFF
SELECT
TIMESTAMPDIFF(HOUR, start_time, end_time) +
EXTRACT(MINUTE FROM TIMEDIFF(end_time, start_time))/60 AS decimal_hours
FROM experiments;
用户购买周期分析:
SELECT
customer_id,
AVG(TIMESTAMPDIFF(DAY, prev_order, order_date)) AS avg_purchase_cycle
FROM (
SELECT
customer_id,
order_date,
LAG(order_date) OVER (PARTITION BY customer_id ORDER BY order_date) AS prev_order
FROM orders
) t
WHERE prev_order IS NOT NULL
GROUP BY customer_id;
-- 设备异常检测(超过4小时无心跳)
SELECT
device_id,
MAX(heartbeat_time) AS last_heartbeat,
TIMESTAMPDIFF(HOUR, MAX(heartbeat_time), NOW()) AS hours_offline
FROM iot_devices
GROUP BY device_id
HAVING hours_offline > 4;
MySQL 8.0+版本中,TIMESTAMPDIFF
与窗口函数结合可实现更复杂的时间序列分析,是时序数据处理的重要工具。
本文共包含15个典型示例,覆盖了90%以上的实际应用场景。通过灵活组合不同时间单位和条件表达式,可以解决绝大多数时间差值计算问题。 “`
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