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/*
最大流模板
isap复杂度(v^2*e)
*/
/*
*State: HDU4280 3609MS 8860K 3571 B C++
*题目大意:
* 有N个岛屿 M条无向路 每个路有一最大允许的客流量,求从最西的那个岛屿最多能运
* 用多少乘客到最东的那个岛屿。
*解题思路:
* 很单纯的网络流,重点是卡时间 模板的高效性很重要啊该模板详解
* 参见这里 模板题就不注释了
*解题感想:
* 10000ms的时间里,大多数最大流算法都挂掉了,就这个坚持下来了,用了3000ms左右。
*/
#include <stdio.h>
#include <iostream>
#include <string.h>
#define VM 100010
#define EM 400010
using namespace std;
const int inf = 0x3f3f3f3f;
struct E
{
int to, frm, nxt, cap;
}edge[EM];
int head[VM], e;//建图时初始化
int dep[VM], gap[VM];//ISAP函数内初始化
void init()
{
e = 0;
memset(head, -1, sizeof(head));
}
void addEdge(int cu, int cv, int cw)
{
edge[e].frm = cu;
edge[e].to = cv;
edge[e].cap = cw;
edge[e].nxt = head[cu];
head[cu] = e++;
edge[e].frm = cv;
edge[e].to = cu;
edge[e].cap = 0;
edge[e].nxt = head[cv];
head[cv] = e++;
}
int que[VM];
void BFS(int des)
{
memset(dep, -1, sizeof(dep));
memset(gap, 0, sizeof(gap));
gap[0] = 1;
int front = 0, rear = 0;
dep[des] = 0;
que[rear++] = des;
int u, v;
while (front != rear)
{
u = que[front++];
front = front%VM;
for (int i=head[u]; i!=-1; i=edge[i].nxt)
{
v = edge[i].to;
if (edge[i].cap != 0 || dep[v] != -1)
continue;
que[rear++] = v;
rear = rear % VM;
++gap[dep[v] = dep[u] + 1];
}
}
}
int cur[VM], stack[VM];
//sap模板
int ISAP(int src, int des, int n)//源点、汇点、图中点的总数
{
int res = 0;
BFS(des);
int top = 0;
memcpy(cur, head, sizeof(head));
int u = src, i;
while (dep[src] < n)
{
if (u == des)
{
int temp = inf, inser = n;
for (i=0; i!=top; ++i)
if (temp > edge[stack[i]].cap)
{
temp = edge[stack[i]].cap;
inser = i;
}
for (i=0; i!=top; ++i)
{
edge[stack[i]].cap -= temp;
edge[stack[i]^1].cap += temp;
}
res += temp;
top = inser;
u = edge[stack[top]].frm;
}
if (u != des && gap[dep[u] -1] == 0)
break;
for (i = cur[u]; i != -1; i = edge[i].nxt)
if (edge[i].cap != 0 && dep[u] == dep[edge[i].to] + 1)
break;
if (i != -1)
{
cur[u] = i;
stack[top++] = i;
u = edge[i].to;
}
else
{
int min = n;
for (i = head[u]; i != -1; i = edge[i].nxt)
{
if (edge[i].cap == 0)
continue;
if (min > dep[edge[i].to])
{
min = dep[edge[i].to];
cur[u] = i;
}
}
--gap[dep[u]];
++gap[dep[u] = min + 1];
if (u != src)
u = edge[stack[--top]].frm;
}
}
return res;
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("in.txt", "r", stdin);
#endif
int n, m, T;
scanf("%d", &T);
while (T--)
{
scanf("%d %d", &n, &m);
int x, y, src, des;
int Min = inf, Max = -inf;
for (int i = 1; i <= n; ++i) //找出起点src 终点des
{
scanf("%d %d", &x, &y);
if (x <= Min)
{
src = i;
Min = x;
}
if (x >= Max)
{
des = i;
Max = x;
}
}
init();
int u, v, c;
for (int i = 0; i != m; ++i)
{
scanf("%d %d %d", &u, &v, &c);
addEdge(u, v, c);
addEdge(v, u, c);
}
int ans = ISAP(src, des, n);
printf("%d\n", ans);
}
return 0;
}
//Isap邻接矩阵版模板
//HDU3549 Isap邻接矩阵版
//46ms
#include <iostream>
#include <cstring>
#include <cstdio>
#define M 16
using namespace std;
const int inf = 0x3f3f3f3f;
int maze[M][M];
int gap[M],dis[M],pre[M],cur[M];
void init()
{
memset(maze, 0, sizeof(maze));
}
//起点是0, 终点是n-1,nodenum为点的个数
int ISAP(int s, int t, int nodenum) {
memset(cur, 0, sizeof(cur));
memset(dis, 0, sizeof(dis));
memset(gap, 0, sizeof(gap));
int u = pre[s] = s,maxflow = 0,aug = inf;
gap[0] = nodenum;
while(dis[s] < nodenum) {
loop:
for(int v = cur[u]; v < nodenum; v++) if(maze[u][v] && dis[u] == dis[v] + 1) {
aug = min(aug, maze[u][v]);
pre[v] = u;
u = cur[u] = v;
if(v == t) {
maxflow += aug;
for(u = pre[u];v != s;v = u,u = pre[u]) {
maze[u][v] -= aug;
maze[v][u] += aug;
}
aug = inf;
}
goto loop;
}
int mindis= nodenum-1;
for(int v = 0; v < nodenum; v++) if(maze[u][v] && mindis> dis[v]) {
cur[u] = v;
mindis= dis[v];
}
if((--gap[dis[u]])== 0) break;
gap[dis[u] = mindis+1] ++;
u = pre[u];
}
return maxflow;
}
int main(void)
{
#ifndef ONLINE_JUDGE
freopen("HDU3549.txt", "r", stdin);
#endif
int n, m, cas, cas_c = 1;
scanf("%d", &cas);
while(cas--)
{
scanf("%d %d", &n, &m);
init();
int u, v, w;
for(int i = 0; i < m; i++)
{
scanf("%d %d %d", &u, &v, &w);
u--, v--;
maze[u][v] += w;
}
int sol = ISAP(0, n-1, n);//起点,终点
printf("Case %d: %d\n", cas_c++, sol);
}
return 0;
}
//State: HDU4280居然用了2700ms+,牛逼模版
/*
This Problem beat me completely.
Beat my template completely.
Beat my funtion comletely.
Waste my time comletely.
It's a naked maximum-stream problem.
The main point is your template.
It make me realize that my SAP template is a sh*t!
....To make my SAP faster, I have done three kinds of optimization.
1. Record the adjacency node which has minimum distance;
2. Initailize the distance by using BFS;
3. As I got a Stack-Overflow, I simulate the DFS by using stack in STL;
Then I got AC in 2s+.
Of course, the problem is also correspond to the Minimum-Cut in Dual-Graph.
Hence, Dijkstra with minimum heap is optimal algorithm.
*/
//Header
//#include <cstdio>
//#include <cstdlib>
//#include <iostream>
//#include <cstring>
//#include <string>
//#include <vector>
//#include <map>
//#include <algorithm>
//#include <cctype>
//#include <queue>
//#include <stack>
//#include <cmath>
//using namespace std;
////Macro
////STL-Alias
//#define UN(c, a) unique(c, a)
//#define MS(c, a) memset(c, a, sizeof c)
//#define FLC(c, a ,b) fill(c, c + a, b)
//#define LOS(c, a, b) lower_bound(c, a, b)
//#define UPS(c, a, b) upper_bound(c, a, b)
////Syntax-Alias
//#define Rep(c, a, b) for (int c = (a); c < (b); c++)
//#define Nre(c, a, b) for (int c = (a); c > (b); c--)
////DEBUG
//#define FK puts("Fu*k here!")
//#define PA(s, c, a, b, p, f){\
// printf(s);\
// Rep(c, a, b) printf(p, (f));\
// puts("");}
////Constant
//#define INFL (0x7fffffffffffffffLL)
//#define INFI (0x7fffffff)
//#define MOD ()
//#define MAXN (100005)
////Type-Alias
//typedef long long LL;
//typedef long double LD;
//typedef int AI[MAXN];
//typedef bool AB[MAXN];
//typedef double AD[MAXN];
//typedef LL ALL[MAXN];
//typedef LD ALD[MAXN];
//
//
////FSG
//struct Edge
//{
// int v, w, next;
//};
//vector<Edge> E;
//AI L;
//void G_ini()
//{
// E.clear();
// MS(L, -1);
//}
//void AE(int u, int v, int w)
//{
// Edge te = {v, w, L[u]};
// L[u] = E.size();
// E.push_back(te);
//}
//#define Ere(c, a, L) for (int c = L[a]; c != -1; c = E[c].next)
//
//
////ISAP
//int ISAP(int src, int snk, int V)
//{
// static AI dis, gap, _L, se;
// int u = src, mxf = 0, te = 0;
// memcpy(_L, L, sizeof L);
// MS(dis, -1); MS(gap, 0);
// gap[dis[snk] = 0] = 1;
// queue<int> Q;
// Q.push(snk);
// while (!Q.empty())
// {
// int u = Q.front(); Q.pop();
// Ere(i, u, L) if (E[i].w && dis[E[i].v] < 0)
// {
// gap[dis[E[i].v] = dis[u] + 1]++;
// Q.push(E[i].v);
// }
// }
// while (dis[src] < V)
// {
// int _i = -1;
// Ere(i, u, _L) if (E[i].w && dis[u] == dis[E[i].v] + 1)
// {
// _i = i;
// break;
// }
// if (_i != -1)
// {
// _L[u] = _i;
// u = E[se[te++] = _i].v;
// }
// else
// {
// int md = INFI;
// _i = -1;
// Ere(i, u, L) if (E[i].w && dis[E[i].v] < md)
// {
// md = dis[E[i].v];
// _L[u] = i;
// }
// if (!--gap[dis[u]]) break;
// gap[dis[u] = md + 1]++;
// if (u != src) u = E[se[te-- - 1] ^ 1].v;
// }
// if (u == snk)
// {
// int _i = 0, mf = INFI;
// Rep(i, 0, te) if (E[se[i]].w < mf)
// {
// mf = E[se[i]].w;
// _i = i;
// }
// Rep(i, 0, te)
// {
// E[se[i]].w -= mf;
// E[se[i] ^ 1].w += mf;
// }
// mxf += mf;
// te = _i;
// u = E[se[_i] ^ 1].v;
// }
// }
// return mxf;
//}
//
//
//struct Isl
//{
// int x, y;
// void inp()
// {
// scanf("%d%d", &x, &y);
// }
//} I[MAXN];
//int n, m;
//
//
//int main()
//{
// int T;
// scanf("%d", &T);
// while (T--)
// {
// //Initialize
// scanf("%d%d", &n, &m);
// I[0].inp();
// int src = 0, snk = 0;
// Rep(i, 1, n)
// {
// I[i].inp();
// if (I[i].x < I[src].x) src = i;
// if (I[i].x > I[snk].x) snk = i;
// }
// G_ini();
// while (m--)
// {
// int u, v, w;
// scanf("%d%d%d", &u, &v, &w);
// u--;
// v--;
// AE(u, v, w);
// AE(v, u, w);
// }
// //Solve
// printf("%d\n", ISAP(src, snk, n));
// }
// return 0;
//}
//
//
//
//
//
//
////isap深搜版,以HDU4280长春网络赛的题目为例,不过那题10000ms都TLE
////不知道dfs版有什么长处,据说dfs版比dinic要快。
//#include <iostream>
//using namespace std;
//
//typedef struct {int v,next,val;} edge;
//const int MAXN=100005;
//const int MAXM=500010;
//const int inf = 0x3f3f3f3f;
//edge e[MAXM];
//int p[MAXN],eid;
//
//inline void init(){memset(p,-1,sizeof(p));eid=0;}
//
////有向
//inline void insert1(int from,int to,int val)
//{
// e[eid].v=to;
// e[eid].val=val;
// e[eid].next=p[from];
// p[from]=eid++;
//
// swap(from,to);
//
// e[eid].v=to;
// e[eid].val=0;
// e[eid].next=p[from];
// p[from]=eid++;
//}
//
////无向
//inline void insert2(int from,int to,int val)
//{
// e[eid].v=to;
// e[eid].val=val;
// e[eid].next=p[from];
// p[from]=eid++;
//
// swap(from,to);
//
// e[eid].v=to;
// e[eid].val=val;
// e[eid].next=p[from];
// p[from]=eid++;
//}
//
//int n,m;//n为点数 m为边数
//int h[MAXN];
//int gap[MAXN];
//
//int source,sink;
//inline int dfs(int pos,int cost)
//{
// if (pos==sink)
// {
// return cost;
// }
//
// int j,minh=n-1,lv=cost,d;
//
// for (j=p[pos];j!=-1;j=e[j].next)
// {
// int v=e[j].v,val=e[j].val;
// if(val>0)
// {
// if (h[v]+1==h[pos])
// {
// if (lv<e[j].val) d=lv;
// else d=e[j].val;
//
// d=dfs(v,d);
// e[j].val-=d;
// e[j^1].val+=d;
// lv-=d;
// if (h[source]>=n) return cost-lv;
// if (lv==0) break;
// }
//
// if (h[v]<minh) minh=h[v];
// }
// }
//
// if (lv==cost)
// {
// --gap[h[pos]];
// if (gap[h[pos]]==0) h[source]=n;
// h[pos]=minh+1;
// ++gap[h[pos]];
// }
//
// return cost-lv;
//
//}
//
//int sap(int st,int ed)
//{
//
// source=st;
// sink=ed;
// int ret=0;
// memset(gap,0,sizeof(gap));
// memset(h,0,sizeof(h));
//
// gap[st]=n;
//
// while (h[st]<n)
// {
// ret+=dfs(st,INT_MAX);
// }
//
// return ret;
//}
//
//
//int main()
//{
//#ifndef ONLINE_JUDGE
// freopen("in.txt", "r", stdin);
//#endif
// int T;
// scanf("%d", &T);
// while (T--)
// {
// scanf("%d%d", &n, &m);
// int x, y;
// int Min = inf, Max = -inf;
// int src, des;
// for (int i=1; i<=n; ++i) //找出起点src 终点des
// {
// scanf("%d%d", &x, &y);
// if (x <= Min)
// {
// src = i;
// Min = x;
// }
// if (x >= Max)
// {
// des = i;
// Max = x;
// }
// }
//
// init();
// int u, v, c;
// for (int i=0; i!=m; ++i)
// {
// scanf("%d%d%d", &u, &v, &c);
// // addedge(u,v,c);
// // addedge(v,u,c);
// insert2(u, v, c);
// }
//
// printf("%d\n", sap(src,des));
// }
// return 0;
//}
//邻接表——sha
#include <iostream>
#include <stdio.h>
#include <algorithm>
#include <functional>
#include <cmath>
#include <cstring>
#include <string>
#include <vector>
#include <map>
#include <set>
#include <utility>
#include <stack>
#include <queue>
#include <deque>
#include <iomanip>
#define VM 10001
#define EM 500100
#define pi 3.1415926535897932
#define abs(x) ((x)>0?(x):-(x))
#define sqr(x) ((x)*(x))
#define fill(m,v) memset(m,v,sizeof(m))
#define SS(x) scanf("%d",&x)
#define inf 0x7fffffff
#define hinf 0x3f3f3f3f
#define fi first
#define se second
#define all(x) x.begin(), x.end()
#define rall(v) v.rbegin(),v.rend()
#define sz(v) ((int)v.size())
#define y0 stupid_cmath
#define y1 very_stupid_cmath
#define ll __int64
#define ull unsigned __int64
#define pb push_back
#define mp make_pair
#define rep(i,m) for(int i=0;i<(int)(m);i++)
#define rep2(i,n,m) for(int i=n;i<(int)(m);i++)
#define FOR(i,a,b) for(int i = (a); i < (b); i++)
#define FF(i,a) for(int i = 0; i < (a); i++ )
#define FFD(i,a) for(int i = (a)-1; i >= 0; i--)
#define CC(m,what) memset(m,what,sizeof(m))
#define SZ(a) ((int)a.size())
#define PP(n,m,a) puts("---");FF(i,n){FF(j,m)cout << a[i][j] << ' ';puts("");}
#define read freopen("in.txt","r",stdin)
#define write freopen("out.txt","w",stdout)
int dx[] = {-1, 0, 1, 0};//up Right down Left
int dy[] = {0, 1, 0, -1};
//#define For(it,c) for(__typeof(c.begin()) it=c.begin();it!=c.end();++it)
using namespace std;
#define M 40010
template<class T> inline void checkmin(T &a,T b) {if(a == -1 || a > b)a = b;}
template<class T> inline void checkmax(T &a,T b) {if(a < b) a = b;}
int gap[M],dis[M],pre[M],cur[M];
int NE,NV;
int head[M];
struct Node{
int c,pos,next;
}E[999999];
int sap(int s,int t) {
memset(dis,0,sizeof(int)*(NV+1));
memset(gap,0,sizeof(int)*(NV+1));
FF(i,NV) cur[i] = head[i];
int u = pre[s] = s,maxflow = 0,aug = -1;
gap[0] = NV;
while(dis[s] < NV) {
loop: for(int &i = cur[u]; i != -1; i = E[i].next) {
int v = E[i].pos;
if(E[i].c && dis[u] == dis[v] + 1) {
checkmin(aug,E[i].c);
pre[v] = u;
u = v;
if(v == t) {
maxflow += aug;
for(u = pre[u];v != s;v = u,u = pre[u]) {
E[cur[u]].c -= aug;
E[cur[u]^1].c += aug;
}
aug = -1;
}
goto loop;
}
}
int mindis = NV;
for(int i = head[u]; i != -1 ; i = E[i].next) {
int v = E[i].pos;
if(E[i].c && mindis > dis[v]) {
cur[u] = i;
mindis = dis[v];
}
}
if( (--gap[dis[u]]) == 0) break;
gap[ dis[u] = mindis+1 ] ++;
u = pre[u];
}
return maxflow;
}
void Insert(int u,int v,int c,int cc = 0) {
E[NE].c = c; E[NE].pos = v;
E[NE].next = head[u]; head[u] = NE++;
E[NE].c = cc; E[NE].pos = u;
E[NE].next = head[v]; head[v] = NE++;
}
int main() {
FF(i,NV) head[i] = -1;
NE = 0;
}
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