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要结合其他SQL功能以提升Aggregation查询能力,您可以考虑以下方法:
SELECT COUNT(*)
FROM (
SELECT *
FROM orders
WHERE order_date >= '2021-01-01'
) AS filtered_orders;
SELECT c.customer_id, COUNT(o.order_id) AS total_orders
FROM customers c
JOIN orders o ON c.customer_id = o.customer_id
GROUP BY c.customer_id;
SELECT customer_id,
SUM(order_amount) OVER (PARTITION BY customer_id) AS total_order_amount
FROM orders;
SELECT product_category, COUNT(*) AS total_products
FROM products
GROUP BY product_category;
SELECT customer_id, COUNT(order_id) AS total_orders
FROM orders
GROUP BY customer_id
HAVING COUNT(order_id) > 5;
SELECT customer_id, COUNT(order_id) AS total_orders
FROM orders
WHERE order_date >= '2021-01-01'
GROUP BY customer_id
UNION ALL
SELECT customer_id, COUNT(order_id) AS total_orders
FROM orders
WHERE order_date < '2021-01-01'
GROUP BY customer_id;
通过结合这些SQL功能,您可以创建更强大、更灵活的聚合查询,以满足您的业务需求。
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